can somebody explain how this works?

问题

I have this line of code.

class ButtonPanel extends JPanel implements ActionListener
{  
    public ButtonPanel()
    {  
        yellowButton = new JButton("Yellow");

and It works, I thought Java needs to know the type of yellowButton before creating an instance of a jButton like this?

JButton yellowButton = new JButton("Yellow");

can somebody explain how this works?

回答1:

If it really does work, then that means yellowButton is probably a class field that you didn't notice.

Check the class again. What you probably have is something more like this:

class ButtonPanel extends JPanel implements ActionListener
{  
    private JButton yellowButton;

    public ButtonPanel()
    {  
        yellowButton = new JButton("Yellow");
        /* this.yellowButton == yellowButton */

        /* etc */
    }
}

If a variable foo cannot be found in a method scope, it automatically falls back to this.foo. In contrast, some languages like PHP do not have this flexibility. (For PHP you always have to do $this->foo instead of $foo to access class fields.)

回答2:

It shouldn't work, You always need to declare the type of your variable. Are you sure you not missing a piece of code somewhere?

Like this at the beggining.

private JButton yellowButton = null;

来源：https://stackoverflow.com/questions/6310649/can-somebody-explain-how-this-works