问题
Im trying to convert a time structure to a FAT timestamp. My code looks like:
unsigned long Fat(tm_struct pTime)
{
unsigned long FatTime = 0;
FatTime |= (pTime.seconds / 2) >> 1;
FatTime |= (pTime.minutes) << 5;
FatTime |= (pTime.hours) << 11;
FatTime |= (pTime.days) << 16;
FatTime |= (pTime.months) << 21;
FatTime |= (pTime.years + 20) << 25;
return FatTime;
}
Does someone have the correct code?
回答1:
The DOS date/time format is a bitmask:
24 16 8 0
+-+-+-+-+-+-+-+-+ +-+-+-+-+-+-+-+-+ +-+-+-+-+-+-+-+-+ +-+-+-+-+-+-+-+-+
|Y|Y|Y|Y|Y|Y|Y|M| |M|M|M|D|D|D|D|D| |h|h|h|h|h|m|m|m| |m|m|m|s|s|s|s|s|
+-+-+-+-+-+-+-+-+ +-+-+-+-+-+-+-+-+ +-+-+-+-+-+-+-+-+ +-+-+-+-+-+-+-+-+
\___________/\________/\_________/ \________/\____________/\_________/
year month day hour minute second
The year is stored as an offset from 1980.
Seconds are stored in two-second increments.
(So if the "second" value is 15, it actually represents 30 seconds.)
I dont know the tm_struct you are using but if it's http://www.cplusplus.com/reference/ctime/tm/ then
unsigned long FatTime = ((pTime.tm_year - 80) << 25) |
(pTime.tm_mon << 21) |
(pTime.tm_mday << 16) |
(pTime.tm_hour << 11) |
(pTime.tm_min << 5) |
(pTime.tm_sec >> 1);
回答2:
Lefteris E gave almost correct answer but here's a little mistake
you should add 1 to tm_mon, because tm struct keeps month as number from 0 to 11 (struct tm), but DOS date/time from 1 to 12 (FileTimeToDosDateTime). so correctly is
unsigned long FatTime = ((pTime.tm_year - 80) << 25) |
((pTime.tm_mon+1) << 21) |
(pTime.tm_mday << 16) |
(pTime.tm_hour << 11) |
(pTime.tm_min << 5) |
(pTime.tm_sec >> 1);
回答3:
Also you can use bit fields and library time.h
. In my project I convert UNIX timestamp to FatFs time.
#include <time.h>
#pragma pack (push,1)
typedef struct{
unsigned Sec :5;
unsigned Min :6;
unsigned Hour :5;
unsigned Day :5;
unsigned Month :4;
unsigned Year :7;
}FatDate_t;
#pragma pack (pop)
DWORD get_fattime(void){
time_t ts=GetDateTimeNow();
struct tm * tmInfo = gmtime( &ts );
uint32_t Result=0;
FatDate_t *fatDate;
fatDate=(FatDate_t *)&Result;
fatDate->Year=tmInfo->tm_year-80;
fatDate->Month=tmInfo->tm_mon+1;
fatDate->Day=tmInfo->tm_mday;
fatDate->Hour=tmInfo->tm_hour;
fatDate->Min=tmInfo->tm_min;
fatDate->Sec=tmInfo->tm_sec>>1;
return Result;
}
来源:https://stackoverflow.com/questions/15763259/unix-timestamp-to-fat-timestamp