问题
I want to start my app which is a hidden app by dialing certain predfined number by me programatically ,for eg *#*#111#*#*
.I open the dialer and input *#*#111#*#*
.Then My app receives the broadcast and starts.Which broadcast should I listen?
回答1:
You should input number *#*#xxxx#*#*
, say, *#*#110#*#*
.
Create a Receiver:
import android.content.BroadcastReceiver;
import android.content.Context;
import android.content.Intent;
public class Listener extends BroadcastReceiver {
@Override
public void onReceive(Context context, Intent intent) {
String pwd = intent.getData().getHost();
Intent i = new Intent(context, CalllistenerActivity.class);
i.putExtra("data", pwd);
i.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(i);
}
}
Create an Activity:
import android.app.Activity;
import android.os.Bundle;
import android.widget.TextView;
public class CalllistenerActivity extends Activity {
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
TextView tv = new TextView(this);
String pwd = getIntent().getStringExtra("data");
tv.setText(TextUtils.isEmpty(pwd)?"Plz input *#*#123#*#* in dial" :pwd);
setContentView(tv);
}
}
Register in AndroidManifest:
<activity android:name=".CalllistenerActivity" android:label="@string/app_name">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<receiver android:name="Listener">
<intent-filter>
<action android:name="android.provider.Telephony.SECRET_CODE" />
<data android:scheme="android_secret_code" android:host="110"/>
</intent-filter>
</receiver>
You should
来源:https://stackoverflow.com/questions/34858721/how-to-start-hidden-app-by-using-call-dialerkeypad-using-android-code