In LISP is it possible to access a function's form?

问题

Suppose I define a function globally:

(defun x (y) (1+ y)) ;; Edit: my first example was too complicated

Is it possible to "coerce" the function x into a list like:

(x (y) (1+ y))

Thanks in advance!

PS - @Danlei's example works in Clozure CL with a special flag, however does anyone know how to get FUNCTION-LAMBDA-EXPRESSION to work in SBCL?

回答1:

You could try FUNCTION-LAMBDA-EXPRESSION:

(function-lambda-expression #'foo)

But it's not guaranteed to work ("… implementations are free to return ``nil, true, nil'' in all cases …").

For example in CCL:

CL-USER> (setq ccl:*save-definitions* t)
T
CL-USER> (defun x (x y) (+ x y))
X
CL-USER> (function-lambda-expression #'x)
(LAMBDA (X Y) (DECLARE (CCL::GLOBAL-FUNCTION-NAME X)) (BLOCK X (+ X Y)))
NIL
X

In SBCL, you might try (setq sb-ext:*evaluator-mode* :interpret) (untested). Maybe there are other ways to achieve this in SBCL (you might look for an analog of *save-definitions* or even try different OPTIMIZE settings), but I don't know about them. Beware that functions entered in the REPL won't be compiled after setting *evaluator-mode* to :interpret, so you will probably experience worse performance.

回答2:

In Common Lisp, you might be able to recover the definition of a function using function-lambda-expression (see the HyperSpec) or in some implementations uncompile-function.

回答3:

When I was spending time on a project to do significant function manipulation, it was easiest to do this sort of thing:

(defclass node ()
  (list-form
   compiled-obj))

First the list form consisting of '(lambda foo (x ) bar) would be assigned, then I would compile Foo and assign it to the compiled-ojb slot.

来源：https://stackoverflow.com/questions/5844670/in-lisp-is-it-possible-to-access-a-functions-form