问题
I'm trying to make a div fadeIn when another div is clicked and fadeOut again when another div is clicked (which would be the close button) but my code doesn't work, did I forget something?
Here's the CSS:
body{
margin: 0;
padding: 0;
text-align: center;
background-color:#f0f2df;
}
#container{
border: solid 1px #f0f2df;
background-color:#f0f2df;
text-align: left;
margin: auto;
width: 939px;
height: 570px;
top:41px;
position:relative;
}
#contact_form{
display: none;
background-image:url(../images/bg.png);
width: 703px;
height: 379px;
position:absolute;
left:236px;
bottom:34px;
}
.contact_close{
display:none;
background-image:url(../images/close.png);
width:17px;
height:17px;
position:absolute;
right:5px;
top:135px;
}
The HTML:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<link rel="stylesheet" type="text/css" href="css/main.css" />
<title>test</title>
<script type='text/javascript' src='js/jquery.js'></script>
<script type='text/javascript' src='js/click.js'></script>
</head>
<body>
<div id="container">
<div class="button_contact"></div>
<div id="contact_form">
<div class="button_close"></div></div>
</div>
</body>
</html>
and the JavaScript
$(document).ready(function(){
$("button_contact").click(function() {
$("#contact_form").fadeIn("slow");
});
$(".contact_close").click(function() {
$("#contact_form").fadeOut("slow");
});
});
回答1:
you need the "." before button_contact
$(document).ready(function(){
$(".button_contact").click(function() {
$("#contact_form").fadeIn("slow");
});
$(".contact_close").click(function() {
$("#contact_form").fadeOut("slow");
});
});
回答2:
jquery also has a .toggle() function that allows you to pass multi-functions that are "toggled" between each other when the element/s are clicked.
http://api.jquery.com/toggle/ a nice function because you can add as many functions as you want.
$(document).ready(function(){
$(".button_contact").toggle(function() {
$("#contact_form").fadeIn("slow");
},
function() {
$("#contact_form").fadeOut("slow");
});
});
回答3:
you forgot a . before button close...
$(".button_contact")....
should work
回答4:
The selector on your fadeIn button is a bit off. Your original code matches an element with a node name of button_contact
not with a class of button_contact
.
Try:
$(".button_contact").click(function() {
$("#contact_form").fadeIn("slow");
});
回答5:
$("button_contact").click(function() { should be
$(".button_contact").click(function() {
回答6:
Try this:
$(document).ready(function(){
$(".button_contact").click(function() {
$("#contact_form").fadeIn("slow");
});
$(".button_close").click(function() {
$("#contact_form").fadeOut("slow");
});
});
回答7:
I'm sorry but will this syntax work if the link being clicked is an ajax link corresponding to another DIV? I can't seem to get it to work!
<script type="text/javascript" src="js/jquery-ajaxLink.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$(".ajaxLink").ajaxLink();
$(".ajaxlink").click(function() {
$("#content").fadeIn("slow");
});
});
</script>
<ul id="mainNav">
<li> <a class="ajaxLink" href="test1.htm">Who We Are </a></li>
<li> <a class="ajaxLink" href="test2.htm">Benefits</a></li>
<li> <a class="ajaxLink" href="test2.htm">Commercial Terms</a></li>
<li> <a class="ajaxLink" href="test3.htm">Property Types</a></li>
<li> <a class="ajaxLink" href="test3.htm">Commercial Info</a></li>
</ul>
<div id="content"></div>
来源:https://stackoverflow.com/questions/1930502/jquery-fadein-fadeout-with-click