php domdocument get node value where attribute value is

折月煮酒 提交于 2019-11-27 01:54:33

问题


Say my XML looks like this:

<record>
  <row name="title">this item</row>
  <row name="url">this url</row>
</record>

Now I'm doing something like this:

$xml = new DOMDocument();
$xml->load('xmlfile.xml');

echo $xml->getElementByTagName('row')->item(0)->attributes->getNamedItem('title')->nodeValue;

But this just gives me:

NOTICE: Trying to get property of non-object id

Does anybody know how to get the node value where the "name" attribute has value "title"?


回答1:


Try:

$xml = new DOMDocument();
$xml->loadXml('
<record>
  <row name="title">this item</row>
  <row name="url">this url</row>
</record>
');

$xpath = new DomXpath($xml);

// traverse all results
foreach ($xpath->query('//row[@name="title"]') as $rowNode) {
    echo $rowNode->nodeValue; // will be 'this item'
}

// Or access the first result directly
$rowNode = $xpath->query('//row[@name="title"][1]')->item(0);
if ($rowNode instanceof DomElement) {
    echo $rowNode->nodeValue;
}



回答2:


foreach ($xml->getElementsByTagName('row') as $element)
{
if ($element->getAttribute('name') == "title")
{
 echo $element->nodeValue;
}
}



回答3:


$xpath = new DOMXPath( $xml );
$val = $xpath->query( '//row[@name="title"]' )->item(0)->nodeValue;


来源:https://stackoverflow.com/questions/6827871/php-domdocument-get-node-value-where-attribute-value-is

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