问题
from lxml import etree
import StringIO
data= StringIO.StringIO('<root xmlns="http://some.random.schema"><a>One</a><a>Two</a><a>Three</a></root>')
docs = etree.iterparse(data,tag='a')
a,b = docs.next()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "iterparse.pxi", line 478, in lxml.etree.iterparse.__next__ (src/lxml/lxml.etree.c:95348)
File "iterparse.pxi", line 534, in lxml.etree.iterparse._read_more_events (src/lxml/lxml.etree.c:95938)
StopIteration
Works fine untill I add the namespace to the root node. Any ideas as to what I can do as a work around, or the correct way of doing this? I need to be event driven due to very large files.
回答1:
When there is a namespace attached, the tag isn't a
, it's {http://some.random.schema}a
. Try this (Python 3):
from lxml import etree
from io import BytesIO
xml = '''\
<root xmlns="http://some.random.schema">
<a>One</a>
<a>Two</a>
<a>Three</a>
</root>'''
data = BytesIO(xml.encode())
docs = etree.iterparse(data, tag='{http://some.random.schema}a')
for event, elem in docs:
print(f'{event}: {elem}')
or, in Python 2:
from lxml import etree
from StringIO import StringIO
xml = '''\
<root xmlns="http://some.random.schema">
<a>One</a>
<a>Two</a>
<a>Three</a>
</root>'''
data = StringIO(xml)
docs = etree.iterparse(data, tag='{http://some.random.schema}a')
for event, elem in docs:
print event, elem
This prints something like:
end: <Element {http://some.random.schema}a at 0x10941e730>
end: <Element {http://some.random.schema}a at 0x10941e8c0>
end: <Element {http://some.random.schema}a at 0x10941e960>
As @mihail-shcheglov pointed out, a wildcard *
can also be used, which works for any or no namespace:
from lxml import etree
from io import BytesIO
xml = '''\
<root xmlns="http://some.random.schema">
<a>One</a>
<a>Two</a>
<a>Three</a>
</root>'''
data = BytesIO(xml.encode())
docs = etree.iterparse(data, tag='{*}a')
for event, elem in docs:
print(f'{event}: {elem}')
See lxml.etree docs for more.
回答2:
Why not with a regular expression ?
1)
Using lxml is slower than using a regex.
from time import clock
import StringIO
from lxml import etree
times1 = []
for i in xrange(1000):
data= StringIO.StringIO('<root ><a>One</a><a>Two</a><a>Three\nlittle pigs</a><b>Four</b><a>another</a></root>')
te = clock()
docs = etree.iterparse(data,tag='a')
tf = clock()
times1.append(tf-te)
print min(times1)
print [etree.tostring(y) for x,y in docs]
import re
regx = re.compile('<a>[\s\S]*?</a>')
times2 = []
for i in xrange(1000):
data= StringIO.StringIO('<root ><a>One</a><a>Two</a><a>Three\nlittle pigs</a><b>Four</b><a>another</a></root>')
te = clock()
li = regx.findall(data.read())
tf = clock()
times2.append(tf-te)
print min(times2)
print li
result
0.000150298431784
['<a>One</a>', '<a>Two</a>', '<a>Three\nlittle pigs</a>', '<a>another</a>']
2.40253998762e-05
['<a>One</a>', '<a>Two</a>', '<a>Three\nlittle pigs</a>', '<a>another</a>']
0.000150298431784 / 2.40253998762e-05 is 6.25
lxml is 6.25 times slower than a regex
.
2)
No problem if namespace:
import StringIO
import re
regx = re.compile('<a>[\s\S]*?</a>')
data= StringIO.StringIO('<root xmlns="http://some.random.schema"><a>One</a><a>Two</a><a>Three\nlittle pigs</a><b>Four</b><a>another</a></root>')
print regx.findall(data.read())
result
['<a>One</a>', '<a>Two</a>', '<a>Three\nlittle pigs</a>', '<a>another</a>']
来源:https://stackoverflow.com/questions/7018326/lxml-iterparse-in-python-cant-handle-namespaces