Regarding python MRO and how super() behaves

问题

Today i was trying to figure out how __mro__ and super works in python, I found something interesting as well as strange to me, because I got something which is not that i understood after reading __mro__. Here is the code snippets.

Code Snippets 1:

#!/usr/bin/pyhon

class A(object):
    def test(self):
        return 'A'

class B(A):
    def test(self):
        return 'B to %s' % super(B, self).test()

class C(A):
    def test(self):
        return 'C'

class D(B, C):
    pass

print D().test()

Output :

 B to C

Code snippet 2: When I update my super inside class B:

#!/usr/bin/pyhon

class A(object):
    def test(self):
        return 'A'

class B(A):
    def test(self):
        return 'B to %s' % super(C, self).test()

class C(A):
    def test(self):
        return 'C'

class D(B, C):
    pass

print D().test()

Output:

B to A

Then now i got what I expected before. Could someone please explain how mro works with super ?

回答1:

The MRO for D is [D, B, C, A, object].

super(C, self) ~ A

super(B, self) ~ C

super(MyClass, self) is not about the "base class of MyClass", but about the next class in the MRO list of MyClass.

As stated in the comments, super(…) actually does not return the next class in the MRO, but delegates calls to it.

来源：https://stackoverflow.com/questions/20545791/regarding-python-mro-and-how-super-behaves