问题
Rails 5.1.2
I have a two models Student
and Award
this way:
class Student < ApplicationRecord
has_many :awards
end
class Award < Application Record
belongs_to :students
# Categories
scope :attendance, -> { where(category: 0) }
#...(other award categories)
scope :talent, -> { where(category: 8) }
# Ranks
# Gold
scope :rank_1, -> { where(rank: 1) }
# Silver
scope :rank_2, -> { where(rank: 2) }
# Bronze
scope :rank_3, -> { where(rank: 3) }
end
Award
has these columns: rank
and category
.
Now, I want to get the top student for a given category. The criteria for this is, order by count of "gold" awards (rank 1
), then order by count of "silver" (rank 2
) awards, and then order by count of "bronze" (rank 3
) awards.
So, if I were to get the Student
who meets the top criteria for category 0
(which is handled by the attendance
scope as described in the model above), this is what I thought the query should look like:
Student.joins(:awards).where(awards: { category: 0 }).group('students.id').order('COUNT(awards.rank == 1) DESC', 'COUNT(awards.rank == 2) DESC', 'COUNT(awards.rank == 3) DESC').take
However, this returns the Student with the highest count of awards, regardless of rank. So for example, if I remove take
, the order looks like this:
# |St.ID | Gold | Slvr. | Brnz. |
----------------------------------
1 | 12 | 4 | 12 | 8 |
----------------------------------
2 | 1 | 9 | 0 | 4 |
----------------------------------
3 | 6 | 9 | 1 | 0 |
----------------------------------
4 | 18 | 5 | 2 | 2 |
----------------------------------
...
So, the order I'm getting are IDs 12, 1, 6, 18, ...
, when it should be IDs 6, 1, 18, 12, ...
.
I realize the order('COUNT(awards.rank == 1) DESC', 'COUNT(awards.rank == 2) DESC', 'COUNT(awards.rank == 3) DESC')
part is simply ordering by the count of awards total (rather than count of a awards with a particular value in column rank
).
I can easily solve this by adding a counter cache for each category of awards, but that isn't an elegant nor flexible solution.
As a bonus, after this query returns a successful result, I will search the database again to find all students who have the same score (as there could be ties). I'm not aware of a way to do all this in one query (perhaps by means of subqueries after getting the values for each rank).
回答1:
I think your problem might be the double equal??
EDIT: This is a more proper way (Assuming MySQL):
Student.joins(:awards).where(awards: { category: 0 }).group('students.id').order('COUNT(if(awards.rank = 1)) DESC', 'COUNT(if(awards.rank = 2)) DESC', 'COUNT(if(awards.rank = 3)) DESC').take
First try your code without it, if that doesn't work, you might want to try this:
SELECT students.id, gold, silver, bronze) FROM students
JOIN ON
(SELECT students.id as id COUNT(awards) as bronze
FROM students JOIN awards ON students.id = awards.student_id
WHERE awards.rank = 1
GROUP BY students.id) q1 q1.id = students.id
JOIN ON
(SELECT students.id as id COUNT(awards) as silver
FROM students JOIN awards ON students.id = awards.student_id
WHERE awards.rank = 2
GROUP BY students.id) q2 q2.id = students.id
JOIN ON
(SELECT students.id as id COUNT(awards) as gold
FROM students JOIN awards ON students.id = awards.student_id
WHERE awards.rank = 3
GROUP BY students.id) q3 q3.id = students.id
ORDER BY gold, silver, bronze
来源:https://stackoverflow.com/questions/45318204/rails-order-by-count-based-on-values-of-column