问题
I'm writing an API server using Django 1.4.2 and Tastypie 0.9.11.
For all the datetime output, I'm using the default iso 8601 format, for example: "2012-11-20T02:48:19+00:00". But I want to get a "2012-11-20T02:48:19Z" format. How to do it easily without customizing each datetime field?
回答1:
Formatting a date is probably best done in the templates. However, Tastypie allows you to add or modify fields returned by the API using the dehydrate cycle. For example:
# models.py
class MyModel(models.Model):
iso8601_date = models.DateTimeField()
class Meta:
verbose_name = 'my_model'
# api.py
class MyResource(ModelResource):
class Meta:
queryset = MyModel.objects.all()
def dehydrate(self, bundle):
# Your original field: bundle.data['iso8601_date']
# Newly formatted field.
bundle.data['new_date_format'] = '2012-11-20T02:48:19Z'
return bundle
Now, if you make the HTTP request, you should see a new line for "new_date_format".
回答2:
There is a configuration called TASTYPIE_DATETIME_FORMATTING in this page http://django-tastypie.readthedocs.org/en/latest/serialization.html. However, this gives you limited options(iso-8601 & rfc-2822).
What you could do is use a custom Serializer for your resource like
# models.py
class MyModel(models.Model):
class Meta:
verbose_name = 'my_model'
# api.py
from custom_serializer import MySerializer
class MyResource(ModelResource):
class Meta:
queryset = MyModel.objects.all()
serializer = MySerializer()
#custom_serializer.py
from tastypie.serializers import Serializer
class MySerializer(Serializer):
def format_datetime(self, data):
return data.strftime("%Y-%m-%dT%H:%M:%SZ")
This has been detailed here - http://django-tastypie.readthedocs.org/en/latest/serialization.html
来源:https://stackoverflow.com/questions/13539901/how-to-change-tastypie-time-format