问题
On my system errno
defined as:
int * __error(void);
#define errno (* __error())
I understand errno
is a macro and expands to * __error()
function:
I searched everywhere (source on my system) but I can't find the definition of the
__error()
function, can someone show/explain what would/should be the definition of it?How the expression
errno = 0
works with the above definition (Assigning0
to a function?)? Doeserrno = 0
expands to* __error() = 0
?
Thanks
回答1:
The __error
function returns a pointer to the errno
variable for the calling thread. The errno
macro dereferences that pointer, resulting in an lvalue that can appear on either side of an equals sign.
To answer your questions:
The function determines the correct address for the
errno
variable for that specific thread. Each thread gets its own.Yes, it becomes
(* __error()) = 0;
which assigns0
to that thread'serrno
variable.
来源:https://stackoverflow.com/questions/14048187/understanding-c-errno