问题
I have a number of objects I would like to paginate using Kaminari. However, on the first page I would also like to show a notification allowing the viewer to create his own object, reducing the number of objects that can be displayed on that page. However, the indicated number of pages should also take into account that this first page contains less elements.
Let's say the objects are the letters a through z. The first page should only 4 display letters: {a,b,c,d}
, while all other pages should show 6 letters: {e,f,g,h,i,j}, {k,l,m,n,o,p}, etc...
I've been looking at the padding
and offset
functions, but I have not yet been able to produce the wanted results with these.
@page
is the current page
if @page == 1
Alphabet.page(@page).per(4)
else
Alphabet.page(@page).per(6).padding(2)
end
=> {a,b,c,d},{i,j,k,l,m,n}, etc...
if @page == 1
Alphabet.page(@page).per(4)
else
Alphabet.page(@page).per(6).offset(4)
end
=> {a,b,c,d},{e,f,g,h,i,j}, {e,f,g,h,i,j} etc...
The offset method also does not set the current_page correctly, so this does not seem like the correct method.
How can I get pagination that looks like {a,b,c,d}, {e,f,g,h,i,j}, {k,l,m,n,o,p}, etc...
, while also displaying the correct number of pages on the first page, in this case 5?
回答1:
After some more digging on the internet, I found an interesting segment in 'Kaminari recipes' about paginating arrays, that used Ruby's instance_eval
method to manually paginate an array.
I tried using this instance_eval
myself, and it seems that this seems to work, although it looks rather hacky
@page = (params[:page] || '1').to_i
if @page == 1
@alphabet = Alphabet.recent.limit(4)
else
@alphabet = Alphabet.recent.limit(6).offset(@page*6-8)
end
@alphabet.instance_eval <<-EVAL
def current_page
#{@page}
end
def total_pages
((Alphabet.all.count+2)/6.0).ceil
end
EVAL
I'm sure there is some better way out there, but since this seems to do the trick for now, I will leave it as is.
回答2:
Buddy, I've found the way of get it working using padding
:
@page = (params[:page] || '1').to_i
@per_page = 4
if @page == "1"
Alphabet.page(@page).per(@per_page - 1)
else
Alphabet.page(@page).per(@per_page).padding(-1)
end
This way, first page will return 3 items and the other pages 4 items.
来源:https://stackoverflow.com/questions/18489398/how-to-set-different-page-size-for-the-first-page-in-kaminari