问题
I'm having a bit of difficulty figuring out what my next steps should be. I am using tastypie to create an API for my web application.
From another application, specifically ifbyphone.com, I am receiving a POST with no headers that looks something like this:
post data:http://myapp.com/api/
callerid=1&someid=2&number=3&result=Answered&phoneid=4
Now, I see in my server logs that this is hitting my server.But tastypie is complaining about the format of the POST.
{"error_message": "The format indicated 'application/x-www-form-urlencoded' had no available deserialization method. Please check your
formats
andcontent_types
on your Serializer.", "traceback": "Traceback (most recent call last):\n\n File \"/usr/local/lib/python2.7/dist-packages/tastypie/resources.py\"
I also receive the same message when I try to POST raw data using curl, which I "believe" is the same basic process being used by ifbyphone's POST method:
curl -X POST --data 'callerid=1&someid=2&number=3&duration=4&phoneid=5' http://myapp.com/api/
So, assuming my problem is actually what is specified in the error message, and there is no deserialization method, how would I go about writing one?
#### Update ######
With some help from this commit ( https://github.com/toastdriven/django-tastypie/commit/7c5ea699ff6a5e8ba0788f23446fa3ac31f1b8bf ) I've been playing around with writing my own serializer, copying the basic framework from the documentation ( https://django-tastypie.readthedocs.org/en/latest/serialization.html#implementing-your-own-serializer )
import urlparse
from tastypie.serializers import Serializer
class urlencodeSerializer(Serializer):
formats = ['json', 'jsonp', 'xml', 'yaml', 'html', 'plist', 'urlencode']
content_types = {
'json': 'application/json',
'jsonp': 'text/javascript',
'xml': 'application/xml',
'yaml': 'text/yaml',
'html': 'text/html',
'plist': 'application/x-plist',
'urlencode': 'application/x-www-form-urlencoded',
}
def from_urlencode(self, data,options=None):
""" handles basic formencoded url posts """
qs = dict((k, v if len(v)>1 else v[0] )
for k, v in urlparse.parse_qs(data).iteritems())
return qs
def to_urlencode(self,content):
pass
回答1:
This worked as expected when I edited my resource model to actually use the serializer class I created. This was not clear in the documentation.
class urlencodeSerializer(Serializer):
formats = ['json', 'jsonp', 'xml', 'yaml', 'html', 'plist', 'urlencode']
content_types = {
'json': 'application/json',
'jsonp': 'text/javascript',
'xml': 'application/xml',
'yaml': 'text/yaml',
'html': 'text/html',
'plist': 'application/x-plist',
'urlencode': 'application/x-www-form-urlencoded',
}
def from_urlencode(self, data,options=None):
""" handles basic formencoded url posts """
qs = dict((k, v if len(v)>1 else v[0] )
for k, v in urlparse.parse_qs(data).iteritems())
return qs
def to_urlencode(self,content):
pass
MyModelResource(ModelResoucre):
class Meta:
...
serializer = urlencodeSerializer() # IMPORTANT
回答2:
I would add a modification to the from_urlencode mentioned in Brandon Bertelsen's post to work better with international characters:
def from_urlencode(self, data, options=None):
""" handles basic formencoded url posts """
qs = {}
for k, v in urlparse.parse_qs(data).iteritems():
value = v if len(v)>1 else v[0]
value = value.encode("latin-1").decode('utf-8')
qs[k] = value
return qs
I'm not sure if this is because of an environmental reason on my side, but I found that when using the following string "ÁáÄäÅåÉéÍíÑñÓóÖöÚúÜü" and the original function, I ran into some problems.
When this string gets URL encoded, it turns into: "%C3%81%C3%A1%C3%84%C3%A4%C3%85%C3%A5%C3%89%C3%A9%C3%8D%C3%AD%C3%91%C3%B1%C3%93%C3%B3%C3%96%C3%B6%C3%9A%C3%BA%C3%9C%C3%BC"
When this gets URL decoded, we have: u'\xc3\x81\xc3\xa1\xc3\x84\xc3\xa4\xc3\x85\xc3\xa5\xc3\x89\xc3\xa9\xc3\x8d\xc3\xad\xc3\x91\xc3\xb1\xc3\x93\xc3\xb3\xc3\x96\xc3\xb6\xc3\x9a\xc3\xba\xc3\x9c\xc3\xbc'
The problem here is that this string appears to be unicode, but it actually isn't, so the above string gets converted to: "ÃáÃäÃÃ¥ÃéÃÃÃñÃóÃÃ"
I found that if I interpreted the URL decoded value as latin-1, and then decoded it for UTF-8, I got the correct original string.
来源:https://stackoverflow.com/questions/14074149/tastypie-with-application-x-www-form-urlencoded