问题
I'm in and android widget and checking elapsed time between two calls of System.nanoTime() and the number is huge. How do you measure elapsed time with this? it should be a fraaction of a second and instead its much more. Thanks
回答1:
The System.nanoTime() returns a time value whose granularity is a nanosecond; i.e. 10-9 seconds, as described in the javadoc. The difference between two calls to System.nanoTime() that are a substantial fraction of a second apart is bound to be a large number.
If you want a time measure with a larger granularity, consider System.currentTimeMillis() ... or just divide the nanosecond values by an appropriate power of 10 to suit your application.
Note that on the Android platform there are 3 distinct system clocks that support different "measures" of time; see SystemClock. If you are programming explicitly for the Android platform, you should read the javadoc and decide which measure is most appropriate to what you are doing.
For your information, "nano-" is one of the standard prefixes defines by the International System of Units (SI) - see http://physics.nist.gov/cuu/Units/prefixes.html.
If you really think that "they" got it wrong and that "nano-" is too small, you could always write a letter to the NIST. I'm sure someone would appreciate it ... :-)
回答2:
One seconds contains 1,000,000,000 nanoseconds, so as long as your number is in that range, it's reasonable.
回答3:
If you want it in fractional form, just take your value / 10^9 where value is your difference in nanoTime()s.
long nanoSeconds = 500000000;
float seconds = nanoSeconds / 1000000000;
Log.i("NanoTime", nanoSeconds + " ns is the same as " + seconds + " seconds");
Your output would be:
07-27 11:35:47.196: INFO/NanoTime(14237): 500000000 ns is the same as 0.5 seconds
来源：https://stackoverflow.com/questions/5023647/java-system-nanotime-huge-difference-in-elapsed-time