问题
I've been participating in a programming contest and one of the problems' input data included a fractional number in a decimal format: 0.75 is one example.
Parsing that into Double is trivial (I can use read for that), but the loss of precision is painful. One needs to be very careful with Double comparisons (I wasn't), which seems redundant since one has Rational data type in Haskell.
When trying to use that, I've discovered that to read a Rational one has to provide a string in the following format: numerator % denominator, which I, obviously, do not have.
So, the question is:
What is the easiest way to parse a decimal representation of a fraction into Rational?
The number of external dependencies should be taken into consideration too, since I can't install additional libraries into the online judge.
回答1:
The function you want is Numeric.readFloat:
Numeric Data.Ratio> fst . head $ readFloat "0.75" :: Rational
3 % 4
回答2:
How about the following (GHCi session):
> :m + Data.Ratio
> approxRational (read "0.1" :: Double) 0.01
1 % 10
Of course you have to pick your epsilon appropriately.
回答3:
Perhaps you'd get extra points in the contest for implementing it yourself:
import Data.Ratio ( (%) )
readRational :: String -> Rational
readRational input = read intPart % 1 + read fracPart % (10 ^ length fracPart)
where (intPart, fromDot) = span (/='.') input
fracPart = if null fromDot then "0" else tail fromDot
来源：https://stackoverflow.com/questions/7056791/how-to-parse-a-decimal-fraction-into-rational-in-haskell