问题
I have the following types:
type GoodResource = {
Id:int;
Field1:string }
type ErrorResource = {
StatusCode:int;
Description:string }
I have the following discriminated union:
type ProcessingResult =
| Good of GoodResource
| Error of ErrorResource
Then want to have a function that will have a return type of the discriminated union ProcessingResult:
let SampleProcessingFunction value =
match value with
| "GoodScenario" -> { Id = 123; Field1 = "field1data" }
| _ -> { StatusCode = 456; Description = "desc" }
Is what I am trying to do possible. The compiler is giving out stating that it expects GoodResource to be the return type. What am I missing or am I completely going about this the wrong way?
回答1:
As it stands, SampleProcessingFunction
returns two different types for each branch.
To return the same type, you need to create a DU (which you did) but also specify the case of the DU explicitly, like this:
let SampleProcessingFunction value =
match value with
| "GoodScenario" -> Good { Id = 123; Field1 = "field1data" }
| _ -> Error { StatusCode = 456; Description = "desc" }
You might ask "why can't the compiler figure out the correct case automatically", but what happens if your DU has two cases of the same type? For example:
type GoodOrError =
| Good of string
| Error of string
In the example below, the compiler cannot determine which case you mean:
let ReturnGoodOrError value =
match value with
| "GoodScenario" -> "Goodness"
| _ -> "Badness"
So again you need to use the constructor for the case you want:
let ReturnGoodOrError value =
match value with
| "GoodScenario" -> Good "Goodness"
| _ -> Error "Badness"
回答2:
You have to state the case of the union type you want to return in either branch.
let SampleProcessingFunction value =
match value with
| "GoodScenario" -> { Id = 123; Field1 = "field1data" } |> Good
| _ -> { StatusCode = 456; Description = "desc" } |> Error
I suggest to read this excellent articles by Scott Wlaschin Railway Oriented Programming
回答3:
{ Id = 123; Field1 = "field1data" }
is a value of type GoodResource
, not of type ProcessingResult
. To create a value of type ProcessingResult
, you need to use one of its two constructors: Good
or Error
.
So your function can be written like this:
let SampleProcessingFunction value =
match value with
| "GoodScenario" -> Good { Id = 123; Field1 = "field1data" }
| _ -> Error { StatusCode = 456; Description = "desc" }
来源:https://stackoverflow.com/questions/29801418/f-can-i-return-a-discriminated-union-from-a-function