问题
The String-conversion to EBCDIC via String.getBytes(charset) supplys at least one false result. The character "a" becomes a 0x3f but should be 0x81.
public static void convert() throws UnsupportedEncodingException {
String data="abcABC";
String ebcdic = "IBM-1047";
String ascii = "ISO-8859-1";
System.out.printf("Charset %s is supported: %s\n", ebcdic, Charset.isSupported(ebcdic));
String result= new String(data.getBytes(ebcdic));
System.out.printf("EBCDIC: %s\n",asHex(result.getBytes()));
System.out.printf("Charset %s is supported: %s\n", ascii, Charset.isSupported(ascii));
result= new String(data.getBytes(ascii));
System.out.printf("ASCII: %s\n",asHex(result.getBytes()));
}
public static String asHex(byte[] buf) {
char[] HEX_CHARS = "0123456789abcdef".toCharArray();
char[] chars = new char[2 * buf.length];
for (int i = 0; i < buf.length; ++i)
{
chars[2 * i] = HEX_CHARS[(buf[i] & 0xF0) >>> 4];
chars[2 * i + 1] = HEX_CHARS[buf[i] & 0x0F];
}
return new String(chars);
}
The result ist:
- Charset IBM-1047 is supported: true
- EBCDIC: 3f8283c1c2c3
- Charset ISO-8859-1 is supported: true
- ASCII: 616263414243
Anything I can do about this?
回答1:
When you call
data.getBytes(ebcdic)
You are encoding the text in data into EBCDIC bytes. Then you create a string from these bytes as if they stood for some string in the default character encoding for your system: this causes breakage because the bytes don't have to encode valid text in any other encoding than EBCDIC.
To fix this, keep bytes as bytes:
byte[] result= data.getBytes(ebcdic);
System.out.printf("EBCDIC: %s\n",asHex(result));
来源:https://stackoverflow.com/questions/18170601/string-getbytescharset-has-errors-for-ebcdic-charset