How to pool objects in Spring?

烈酒焚心 提交于 2019-12-09 18:14:36

问题


I'm following this tutorial regarding how to pool objects in Spring. I've followed the instruction written on the tutorial but when I run my application, it always generates a new instance of the object. I'm expecting that since I'm pooling the objects, existing objects will be reuse. As such, no new instances should be created. Also, when I access of the getter method of the bean, a new instance of the bean is created again.

What could have I done wrong? Did I misunderstood the concept of pooling in Spring?

Below is my code:

Application Context: (This is just the body of my application context.)

<bean id="simpleBeanTarget" class="com.bean.SimpleBean" scope="prototype">

</bean>

<bean id="poolTargetSource" class="org.springframework.aop.target.CommonsPoolTargetSource">
    <property name="targetBeanName" value="simpleBeanTarget" />
    <property name="maxSize" value="2" />
</bean>

<bean id="simpleBean" class="org.springframework.aop.framework.ProxyFactoryBean">
    <property name="targetSource" ref="poolTargetSource" />
</bean>

The controller: (This is just the body of my method)

@RequestMapping("/hello")
public ModelAndView helloWorld(HttpServletRequest request, HttpServletResponse response)
{
    String message = "Hello World, Spring 3.";
    try
    {
        System.out.println("Accessing Application Context");
        ApplicationContext context = new ClassPathXmlApplicationContext("applicationContext.xml");

        System.out.println("Getting Bean");
        SimpleBean simpleBean = (SimpleBean) context.getBean("simpleBean");
        //A new SimpleBean... is printed here.

        System.out.println("Displaying Hello World: " + simpleBean.getRandomNum());
        //After this line, A new SimpleBean... is printed again. I simply access the getter method. Why does it create a new instance of SimpleBean?

        return new ModelAndView("hello", "message", message);
    }catch(Exception e)
    {
        System.out.println("Error: " + e);
        e.printStackTrace();
        return new ModelAndView("hello", "message", "Error! " + e.getMessage());
    }
}

The bean I'm pooling:

package com.bean;

import java.util.Random;

public class SimpleBean
{
    int randomNum;
    String str;

    SimpleBean()
    {
        Random randomGenerator = new Random();
        randomNum = randomGenerator.nextInt(100);

        //I'm printing this line just to check if a instance of this bean is created.
        System.out.println("#####################A new SimpleBean was born: " + randomNum);

        str = "This is a string.";
    }

    public int getRandomNum()
    {
        return randomNum;
    }

    public void setRandomNum(int randomNum)
    {
        this.randomNum = randomNum;
    }

    public String getStr()
    {
        if (str == null)
            return "str is null";
        return str;
    }

    public void setStr(String str)
    {
        this.str = str;
    }
}

The body of my web.xml:

<display-name>Spring3MVC</display-name>

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/classes/applicationContext.xml</param-value>
</context-param>

<welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
</welcome-file-list>

<servlet>
    <servlet-name>spring</servlet-name>
    <servlet-class>
        org.springframework.web.servlet.DispatcherServlet
    </servlet-class>
    <load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
    <servlet-name>spring</servlet-name>
    <url-pattern>*.html</url-pattern>
</servlet-mapping>

回答1:


On each request, you create a brand new Spring application context, then you get new object in a new applicatin context each action. so you should load your spring context use 'ContextLoaderListener' in web.xml.

Reference fragment in web.xml

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>
        classpath*:spring/appContext.xml  classpath*:spring/appContext-security.xml
    </param-value>
</context-param>

<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

See you code:

try
{
    System.out.println("Accessing Application Context");
    ApplicationContext context = new ClassPathXmlApplicationContext("applicationContext.xml");
   ...

For more knowledge about Spring context loading, see MKyong 's tutorial or Spring reference




回答2:


When you mention it means you are saying to service provider of urs pooling that you want to create maximum of two objects with object state provided via urs constructor.

  SimpleBean()
    {
        Random randomGenerator = new Random();
        randomNum = randomGenerator.nextInt(100);

        //I'm printing this line just to check if a instance of this bean is created.
        System.out.println("#####################A new SimpleBean was born: " + randomNum);

        str = "This is a string.";

    }

so SimpleBean simpleBean = (SimpleBean) context.getBean("simpleBean"); is a pooled object. iF two execution path want to get service from simpleBean then that object instance is provided via Pooling.If more thean two execution path then it is provided via prototype scope.




回答3:


Try this will work...

<property name="targetSource" ref="poolTargetSource" />

<!-- Added so that different instance of object is created -->
<property name="singleton" value="false" />



来源:https://stackoverflow.com/questions/15472935/how-to-pool-objects-in-spring

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