问题
I want to jump a function from a chain of waterfall functions with asyncjs
in nodejs
.
My code look like this :
async.waterfall([
function(next){
if(myBool){
next(null);
}else{
// Bypass the 2nd function
}
},
// I want to bypass this method if myBool is false in the 1st function
function(next){
},
// Always called
function(next){
}
]);
Do you know a proper way to do this without put :
if(!myBool){
return next();
}
In the function I want to bypass.
Thanks !
回答1:
An alternative might be:
var tasks = [f1];
if(myBool){
tasks.push(f2);
}
tasks.push(f3);
async.waterfall(tasks, function(err, result){
});
where f1
, f2
, and f3
are your functions.
other than that, you're better off doing it explicitly, avoid making your code overly complicated, simpler is usually better
update:
function f1(done){
if(myBool){
f2(done);
}else{
done();
}
}
function f2(done){
async.nextTick(function(){
// stuff
done();
});
}
async.waterfall([f1,f3],function(err,result){
// foo
});
回答2:
I think this should work:
var finalCallback = function(err, result){
if(err)
// handle error..
else
console.log('end! :D');
}
async.waterfall(
[
function step1(callback){
// stuff
callback(null, someData);
},
function step2(someData, callback){
if(skip_step_3)
finalCallback(null, someData);
else
callback(null, someData);
},
function step3(moreData, callback){
// more stuff
callback(null, moreData);
}
],
finalCallback
)
the creator of async recomend this in the github repo (https://github.com/caolan/async/pull/85)
回答3:
Using if-async module your code will look like this:
var async = require('async')
var ifAsync = require('if-async')
async.waterfall([
foo,
ifAsync(p1).then(c1).else(c2),
bar
], function(err) {})
for full example take a look here: https://github.com/kessler/if-async#example-2-using-with-asyncjs-waterfall
回答4:
I am late to answer, but async-if-else might help you.
Sample Code
var async = require('async-if-else')(require('async'));
function emailExists(user, callback) {
user.find(user.email, function(err, dbUser){
if (err)
return callback(error);
if(!dbUser)
return callback(null, false); // does not exist, predicate will be false
callback(null, true);
});
}
function updateAccount(user, callback) {
user.update( ..., callback);
}
function importFromLegacyByEmail(user, callback) {
remoteClient.get(user, callback);
}
async.waterfall([
async.constant({email: 'thiago@email.com', dogs: 2, money: 0, fun: 100 }),
async.if(emailExists, updateAccount).else(importFromLegacyByEmail),
sendEmail
], handler);
回答5:
I would recommend using clojurescript which has an awesome core-async library which makes life super easy when dealing with async calls.
In your case, you would write something like this:
(go
(when-let [res1 (<! (asyncFunc1))]
(<! (asyncFunc2 res1)))
(<! (asyncFunc3)))
Note the go
macro which will cause the body to run asynchronously, and the <!
function which will block until the async functions will return.
The code will first block on the first async function. Then, if the result of that is true, it will run the second async function on block on that as well. Lastly, it will run the third async function and block on that.
来源:https://stackoverflow.com/questions/15420019/asyncjs-bypass-a-function-in-a-waterfall-chain