Get file size from “Content-Length” value from a file in python 3.2

旧时模样 提交于 2019-12-09 11:06:03

问题


I want to get the Content-Length value from the meta variable. I need to get the size of the file that I want to download. But the last line returns an error, HTTPMessage object has no attribute getheaders.

import urllib.request
import http.client

#----HTTP HANDLING PART----
 url = "http://client.akamai.com/install/test-objects/10MB.bin"

file_name = url.split('/')[-1]
d = urllib.request.urlopen(url)
f = open(file_name, 'wb')

#----GET FILE SIZE----
meta = d.info()

print ("Download Details", meta)
file_size = int(meta.getheaders("Content-Length")[0])

回答1:


It looks like you are using Python 3, and have read some code / documentation for Python 2.x. It is poorly documented, but there is no getheaders method in Python 3, but only a get_all method.

See this bug report.




回答2:


for Content-Length:

file_size = int(d.getheader('Content-Length'))



回答3:


You should consider using Requests:

import requests

url = "http://client.akamai.com/install/test-objects/10MB.bin"
resp = requests.get(url)

print resp.headers['content-length']
# '10485760'

For Python 3, use:

print(resp.headers['content-length'])

instead.




回答4:


Change final line to:

file_size = int(meta.get_all("Content-Length")[0])



回答5:


response.headers['Content-Length'] works on both Python 2 and 3:

#!/usr/bin/env python
from contextlib import closing

try:
    from urllib2 import urlopen
except ImportError: # Python 3
    from urllib.request import urlopen


with closing(urlopen('http://stackoverflow.com/q/12996274')) as response:
    print("File size: " + response.headers['Content-Length'])



回答6:


import urllib.request

link = "<url here>"

f = urllib.request.urlopen(link)
meta = f.info()
print (meta.get("Content-length"))
f.close()

Works with python 3.x



来源:https://stackoverflow.com/questions/12996274/get-file-size-from-content-length-value-from-a-file-in-python-3-2

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