问题
I want to create a thread pool for experimental purposes (and for the fun factor). It should be able to process a wide variety of tasks (so I can possibly use it in later projects).
In my thread pool class I'm going to need some sort of task queue. Since the Standard Library provides std::packaged_task since the C++11 standard, my queue will look like std::deque<std::packaged_task<?()> > task_queue, so the client can push std::packaged_tasks into the queue via some sort of public interface function (and then one of the threads in the pool will be notified with a condition variable to execute it, etc.).
My question is related to the template argument of the std::packaged_task<?()>s in the deque.
The function signature ?() should be able to deal with any type/number of parameters, because the client can do something like:
std::packaged_task<int()> t(std::bind(factorial, 342));
thread_pool.add_task(t);
So I don't have to deal with the type/number of parameters.
But what should the return value be? (hence the question mark)
If I make my whole thread pool class a template class, one instance of it will only be able to deal with tasks with a specific signature (like
std::packaged_task<int()>).I want one thread pool object to be able to deal with any kind of task.
If I go with
std::packaged_task<void()>and the function invoked returns an integer, or anything at all, then thats undefined behaviour.
回答1:
So the hard part is that packaged_task<R()> is move-only, otherwise you could just toss it into a std::function<void()>, and run those in your threads.
There are a few ways around this.
First, ridiculously, use a packaged_task<void()> to store a packaged_task<R()>. I'd advise against this, but it does work. ;) (what is the signature of operator() on packaged_task<R()>? What is the required signature for the objects you pass to packaged_task<void()>?)
Second, wrap your packaged_task<R()> in a shared_ptr, capture that in a lambda with signature void(), store that in a std::function<void()>, and done. This has overhead costs, but probably less than the first solution.
Finally, write your own move-only function wrapper. For the signature void() it is short:
struct task {
template<class F,
class dF=std::decay_t<F>,
class=decltype( std::declval<dF&>()() )
>
task( F&& f ):
ptr(
new dF(std::forward<F>(f)),
[](void* ptr){ delete static_cast<dF*>(ptr); }
),
invoke([](void*ptr){
(*static_cast<dF*>(ptr))();
})
{}
void operator()()const{
invoke( ptr.get() );
}
task(task&&)=default;
task&operator=(task&&)=default;
task()=default;
~task()=default;
explicit operator bool()const{return static_cast<bool>(ptr);}
private:
std::unique_ptr<void, void(*)(void*)> ptr;
void(*invoke)(void*) = nullptr;
};
and simple. The above can store packaged_task<R()> for any type R, and invoke them later.
This has relatively minimal overhead -- it should be cheaper than std::function, at least the implementations I've seen -- except it does not do SBO (small buffer optimization) where it stores small function objects internally instead of on the heap.
You can improve the unique_ptr<> ptr container with a small buffer optimization if you want.
回答2:
I happen to have an implementation which does exactly that. My way of doing things is to wrap the std::packaged_task objects in a struct which abstracts away the return type. The method which submits a task into the thread pool returns a future on the result.
This kind of works, but due to the memory allocations required for each task it is not suitable for tasks which are very short and very frequent (I tried to use it to parallelize chunks of a fluid simulation and the overhead was way too high, in the order of several milliseconds for 324 tasks).
The key part is this structure:
struct abstract_packaged_task
{
template <typename R>
abstract_packaged_task(std::packaged_task<R> &&task):
m_task((void*)(new std::packaged_task<R>(std::move(task)))),
m_call_exec([](abstract_packaged_task *instance)mutable{
(*(std::packaged_task<R>*)instance->m_task)();
}),
m_call_delete([](abstract_packaged_task *instance)mutable{
delete (std::packaged_task<R>*)(instance->m_task);
})
{
}
abstract_packaged_task(abstract_packaged_task &&other);
~abstract_packaged_task();
void operator()();
void *m_task;
std::function<void(abstract_packaged_task*)> m_call_exec;
std::function<void(abstract_packaged_task*)> m_call_delete;
};
As you can see, it hides away the type dependencies by using lambdas with std::function and a void*. If you know the maximum size of all possibly occuring std::packaged_task objects (I have not checked whether the size has a dependency on R at all), you could try to further optimize this by removing the memory allocation.
The submission method into the thread pool then does this:
template <typename R>
std::future<R> submit_task(std::packaged_task<R()> &&task)
{
assert(m_workers.size() > 0);
std::future<R> result = task.get_future();
{
std::unique_lock<std::mutex> lock(m_queue_mutex);
m_task_queue.emplace_back(std::move(task));
}
m_queue_wakeup.notify_one();
return result;
}
where m_task_queue is an std::deque of abstract_packaged_task structs. m_queue_wakeup is a std::condition_variable to wake a worker thread up to pick up the task. The worker threads implementation is as simple as:
void ThreadPool::worker_impl()
{
std::unique_lock<std::mutex> lock(m_queue_mutex, std::defer_lock);
while (!m_terminated) {
lock.lock();
while (m_task_queue.empty()) {
m_queue_wakeup.wait(lock);
if (m_terminated) {
return;
}
}
abstract_packaged_task task(std::move(m_task_queue.front()));
m_task_queue.pop_front();
lock.unlock();
task();
}
}
You can take a look at the full source code and the corresponding header on my github.
来源：https://stackoverflow.com/questions/31072279/implementing-a-simple-generic-thread-pool-in-c11