问题
I have come across this example from wikipedia regarding weak reference:
import java.lang.ref.WeakReference;
public class ReferenceTest {
public static void main(String[] args) throws InterruptedException {
WeakReference r = new WeakReference(new String("I'm here"));
WeakReference sr = new WeakReference("I'm here");
System.out.println("before gc: r=" + r.get() + ", static=" + sr.get());
System.gc();
Thread.sleep(100);
// only r.get() becomes null
System.out.println("after gc: r=" + r.get() + ", static=" + sr.get());
}
}
I don't understand in this scenario why only r.get() returns null but not the sr.get(). Can someone let me know the reason?
Many thanks.
回答1:
the literal "I'm here"
is a compile time constant string and as such gets placed in the constant string pool, which (up until java 7) was never garbage collected. that means sr
points to an object that will never be garbage collected.
r
, on the other hand, points to a copy of that string, which is not in any const pool and so is eligible for collection.
see the documentation for String.intern() for some more details on this string pool
回答2:
If this reference object has been cleared, either by the program or by the garbage collector, then this method returns null.
very well explained here
来源:https://stackoverflow.com/questions/20121173/weakreference-to-string-and-string-constants