Why $'\0' or $'\x0' is an empty string? Should be the null-character, isn't it?

问题

bash allows $'string' expansion. My man bash says:

Words of the form $'string' are treated specially. The word expands to string, with backslash-escaped characters replaced as specified by the ANSI C standard. Backslash escape sequences, if present, are decoded as follows:
\a alert (bell)
\b backspace
\e
\E an escape character
\f form feed
\n new line
\r carriage return
\t horizontal tab
\v vertical tab
\ backslash
\' single quote
\" double quote
\nnn the eight-bit character whose value is the octal value nnn (one to three digits)
\xHH the eight-bit character whose value is the hexadecimal value HH (one or two hex digits)
\cx a control-x character

The expanded result is single-quoted, as if the dollar sign had not been present.

But why does bash not convert $'\0' and $'\x0' into a null character?
Is it documented? Is there a reason? (Is it a feature or a limitation or even a bug?)

$ hexdump -c <<< _$'\0'$'\x1\x2\x3\x4_'
0000000   _ 001 002 003 004   _  \n
0000007

echo gives the expected result:

> hexdump -c < <( echo -e '_\x0\x1\x2\x3_' )
0000000   _  \0 001 002 003   _  \n
0000007

My bash version

$ bash --version | head -n 1
GNU bash, version 4.1.2(1)-release (x86_64-redhat-linux-gnu)

Why echo $'foo\0bar' does not behave as echo -e 'foo\0bar'?

回答1:

It's a limitation. bash does not allow string values to contain interior NUL bytes.

Posix (and C) character strings cannot contain interior NULs. See, for example, the Posix definition of character string (emphasis added):

3.92 Character String

A contiguous sequence of characters terminated by and including the first null byte.

Similarly, standard C is reasonably explicit about the NUL character in character strings:

§5.2.1p2 …A byte with all bits set to 0, called the null character, shall exist in the basic execution character set; it is used to terminate a character string.

Posix explicitly forbids the use of NUL (and /) in filenames (XBD 3.170) or in environment variables (XBD 8.1 "... are considered to end with a null byte."

In this context, shell command languages, including bash, tend to use the same definition of a character string, as a sequence of non-NUL characters terminated by a single NUL.

You can pass NULs freely through bash pipes, of course, and nothing stops you from assigning a shell variable to the output of a program which outputs a NUL byte. However, the consequences are "unspecified" according to Posix (XSH 2.6.3 "If the output contains any null bytes, the behavior is unspecified."). In bash, the NULs are removed, unless you insert a NUL into a string using bash's C-escape syntax ($'\0'), in which case the NUL will end up terminating the value.

On a practical note, consider the difference between the two following ways of attempting to insert a NUL into the stdin of a utility:

$ # Prefer printf to echo -n
$ printf $'foo\0bar' | wc -c
3
$ printf 'foo\0bar' | wc -c
7
$ # Bash extension which is better for strings which might contain %
$ printf %b 'foo\0bar' | wc -c
7

回答2:

But why does bash not convert $'\0' and $'\x0' into a null character?

Because a null character terminates a string.

$ echo $'hey\0you'
hey

回答3:

It is a null character, but it depends on what you mean by that.

The null character represents an empty string, which is what you get when you expand it. It is a special case and I think that is implied by the documentation but not actually stated.

In C binary zero '\0' terminates a string and on its own also represents an empty string. Bash is written in C, so it probably follows from that.

Edit: POSIX mentions a null string in a number of places. In the "Base definitions" it defines a null string as:

3.146 Empty String (or Null String)
A string whose first byte is a null byte.

来源：https://stackoverflow.com/questions/19227564/why-0-or-x0-is-an-empty-string-should-be-the-null-character-isnt-it