问题
I've searched on how to do this in python and I can't find an answer. If you have a string:
>>> value = 'abc'
How would you increment all characters in a string by 1? So the input that I'm looking for is:
>>> value = 'bcd'
I know I can do it with one character using ord and chr:
>>> value = 'a'
>>> print (chr(ord(value)+1))
>>> b
But ord()
and chr()
can only take one character. If I used the same statement above with a string of more than one character. I would get the error:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: ord() expected a character, but string of length 3 found
Is there a way to do this?
回答1:
You could use a generator expression with ''.join()
as follows:
In [153]: value = 'abc'
In [154]: value_altered = ''.join(chr(ord(letter)+1) for letter in value)
In [155]: value_altered
Out[155]: 'bcd'
The generator iterates over each letter
in the string value
and increments it by one using the chr(ord(letter)+1)
methodology suggested in your question. It then uses ''.join()
to convert the letters in the generator back into a string.
回答2:
As gtllambert beat me to my original answer, I am posting an alternative solution. You can also use map
and a lambda expression to achieve the same. The lambda expression uses chr
and ord
to increment each character by one and chr
is used to convert it back to a character.
value = 'abc'
''.join(map(lambda x:chr(ord(x)+1),value))
回答3:
value = 'abc'
newVar=(chr(ord(value[0])+1))
newVar1=(chr(ord(value[1])+1))
newVar2=(chr(ord(value[2])+1))
value=newVar+newVar1+newVar2
print(value)
Here is what I came up with can't believe it actually worked thanks for the challenge using python 3
回答4:
Very simple four line piece of code:
finalMessage=""
for x in range (0,len(value)):
finalMessage+=(chr(ord(value[x])+1))
print(finalMessage)
It goes through each letter in the string and adds one to it, but this doesn't work with "z", so you could do:
value="abc testing testing, or sdrshmf"
finalMessage=""
for x in range(0,len(value)):
if ord(value[x]) in range(97,123):
finalMessage+=(chr(((ord(value[x])-96)%26)+97))
elif ord(value[x]) in range(65,91):
finalMessage+=(chr(((ord(value[x])-64)%26)+65))
else:
finalMessage+=value[x]
print(finalMessage)
来源:https://stackoverflow.com/questions/35820678/python-increment-characters-in-a-string-by-1