问题
Number.prototype.isInteger = Number.prototype.isInteger || function(x) {
return (x ^ 0) === x;
}
console.log(Number.isInteger(1));
will throw error in IE10 browser
回答1:
Apparently, IE treats DOM objects and Javascript objects separately, and you can't extend the DOM objects using Object.prototype.
IE doesn't let you use a prototype that is not native..
You'll have to make a separate function (global if you want) as
function isInteger(num) {
return (num ^ 0) === num;
}
console.log(isInteger(1));
回答2:
Notwithstanding possible issues with adding to native prototypes in MSIE, your function body is inappropriate for a method added to Number.prototype
.
Methods on the prototype are called on instances of the type, and the instance is passed as this
(and will always be an object, not a primitive).
Therefore a more correct implementation would be:
Number.prototype.isInteger = function() {
return (this ^ 0) === +this;
}
with usage:
(1).isInteger();
If you wanted to use Number.isInteger(n)
instead, you would have had to add your function directly to the Number
object, not its prototype. There's a rigorous shim for this on the MDN page for this function.
回答3:
Create a polyfill Number.isInteger
Number.isInteger = Number.isInteger || function(value) {
return typeof value === "number" &&
isFinite(value) &&
Math.floor(value) === value;
};
This should solve the issue related to IE.
来源:https://stackoverflow.com/questions/26482645/number-isintegerx-which-is-created-can-not-work-in-ie