Directory.GetFiles: how to get only filename, not full path? [duplicate]

谁说胖子不能爱 提交于 2019-11-27 00:49:43

问题


Possible Duplicate:
How to get only filenames within a directory using c#?

Using C#, I want to get the list of files in a folder.
My goal: ["file1.txt", "file2.txt"]

So I wrote this:

string[] files = Directory.GetFiles(dir);

Unfortunately, I get this output: ["C:\\dir\\file1.txt", "C:\\dir\\file2.txt"]

I could strip the unwanted "C:\dir\" part afterward, but is there a more elegant solution?


回答1:


You can use System.IO.Path.GetFileName to do this.

E.g.,

string[] files = Directory.GetFiles(dir);
foreach(string file in files)
    Console.WriteLine(Path.GetFileName(file));

While you could use FileInfo, it is much more heavyweight than the approach you are already using (just retrieving file paths). So I would suggest you stick with GetFiles unless you need the additional functionality of the FileInfo class.




回答2:


Try,

  string[] files =  new DirectoryInfo(dir).GetFiles().Select(o => o.Name).ToArray();

Above line may throw UnauthorizedAccessException. To handle this check out below link

C# Handle System.UnauthorizedAccessException in LINQ




回答3:


Have a look at using FileInfo.Name Property

something like

string[] files = Directory.GetFiles(dir); 

for (int iFile = 0; iFile < files.Length; iFile++)
    string fn = new FileInfo(files[iFile]).Name;

Also have a look at using DirectoryInfo Class and FileInfo Class




回答4:


Use this to obtain only the filename.

Path.GetFileName(files[0]);


来源:https://stackoverflow.com/questions/12524398/directory-getfiles-how-to-get-only-filename-not-full-path

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