问题
I am trying to unzip an archive (test.zip) containing a subfolder with some png images:
test.zip
| -> images
| -> a.png
| -> b.png
Here is what I do:
public static void unzip(String archive, File baseFolder, String[] ignoreExtensions) {
FileInputStream fin;
try {
fin = new FileInputStream(archive);
ZipInputStream zin = new ZipInputStream(fin);
ZipEntry ze = null;
while ((ze = zin.getNextEntry()) != null) {
if (ignoreExtensions == null || !ignoreEntry(ze, ignoreExtensions)) {
File destinationFile = new File(baseFolder, ze.getName());
unpackEntry(destinationFile, zin);
}
}
zin.close();
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
private static void unpackEntry(File destinationFile, ZipInputStream zin) {
createParentFolder(destinationFile);
FileOutputStream fout = null;
try {
fout = new FileOutputStream(destinationFile);
for (int c = zin.read(); c != -1; c = zin.read()) {
fout.write(c);
zin.closeEntry();
fout.close();
}
} catch (IOException e) {
e.printStackTrace();
}
}
private static void createParentFolder(File destinationFile) {
File parent = new File(destinationFile.getParent());
parent.mkdirs();
}
The images are extracted to the correct location but are corrupt (the size is smaller than expected so I assume they are not decompressed).
If I open the test.zip file with 7Zip it works fine. Any ideas on how to unzip an archive with subfolders?
回答1:
What are you doing here?
for (int c = zin.read(); c != -1; c = zin.read()) {
fout.write(c);
zin.closeEntry();
fout.close();
}
Could it be that you meant this instead?
for (int c = zin.read(); c != -1; c = zin.read()) {
fout.write(c);
}
zin.closeEntry();
fout.close();
回答2:
It can be done as below by checking whether the unzipped entry is a directory. If directory then create the directory and proceed with streaming the file inside the directory.
private void unZipFile(long lBatchID, String sFileName) throws Exception {
final int BUFFER = 2048;
BufferedOutputStream dest = null;
FileInputStream fis = null;
ZipInputStream zis = null;
int iSubstr1 = sFileName.indexOf("-");
int iSubstr2 = sFileName.lastIndexOf("-");
int iEDocketSubStr = sFileName.lastIndexOf("\\");
String sBatchNum = sFileName.substring(iSubstr1 + 1,
iSubstr2);
String sEDocketNum = sFileName.substring(iEDocketSubStr + 1,
iSubstr1);
Date startTime = new Date();
try {
fis = new FileInputStream(sFileName);
zis = new ZipInputStream(
new BufferedInputStream(fis));
ZipEntry entry;
String sTempDir = TEMP_DIR + "\\" + sEDocketNum+"-"+sBatchNum;
File fTempDir = new File(sTempDir);
fTempDir.mkdirs();
while ((entry = zis.getNextEntry()) != null) {
int count;
byte data[] = new byte[BUFFER];
if(entry.isDirectory())
{
File f2 = new File(TEMP_DIR + "\\" + sEDocketNum+"-"+sBatchNum+"\\"+entry.getName());
f2.mkdir();
logger.debug("Creating directory during unzip....."+entry.getName());
}
else
{
FileOutputStream fos = new FileOutputStream(new File(sTempDir
+ "\\" + entry.getName()));
dest = new BufferedOutputStream(fos, BUFFER);
while ((count = zis.read(data, 0, BUFFER)) != -1) {
dest.write(data, 0, count);
}
dest.flush();
dest.close();
}
}
zis.close();
LogTaskDuration.logDuration(lBatchID, startTime, "UNZIP");
} catch (Exception e) {
e.printStackTrace();
logger.error("Problem unzipping file - " + sFileName);
throw new Exception(
"Could not create temporary directory to unzip file");
}
finally
{
if(dest != null)
dest.close();
if(fis!=null)
fis.close();
}
}
来源:https://stackoverflow.com/questions/6364018/unzip-archive-with-subfolders-in-java