问题
I have a string that will be exploded to get an array, and as we know, the output array key will start from 0 as the key to the first element, 1 for the 2nd and so on.
Now how to force that array to start from 1 and not 0?
It's very simple for a typed array as we can write it like this:
array('1'=>'value', 'another value', 'and another one');
BUT for an array that is created on the fly using explode, how to do it?
Thanks.
回答1:
$exploded = explode('.', 'a.string.to.explode');
$exploded = array_combine(range(1, count($exploded)), $exploded);
var_dump($exploded);
Done!
回答2:
Just use a separator to create a dummy element in the head of the array and get rid of it afterwards. It should be the most efficient way to do the job:
function explode_from_1($separator, $string) {
$x = explode($separator, $separator.$string);
unset($x[0]);
return $x;
}
a more generic approach:
function explode_from_x($separator, $string, $offset=1) {
$x = explode($separator, str_repeat($separator, $offset).$string);
return array_slice($x,$offset,null,true);
}
回答3:
$somearray = explode(",",$somestring);
foreach($somearray as $key=>$value)
{
$otherarray[$key+1] = $value;
}
well its dirty but isn't that what php is for...
回答4:
Nate almost had it, but needed a temporary variable:
$someArray = explode(",",$myString);
$tempArray = array();
foreach($someArray as $key=>$value) {
$tempArray[$key+1] = $value;
}
$someArray = $tempArray;
codepad example
回答5:
$array = array('a', 'b', 'c', 'd');
$flip = array_flip($array);
foreach($flip as &$element) {
$element++;
}
$normal = array_flip($flip);
print_r($normal);
Try this, a rather funky solution :P
EDIT: Use this instead.
$array = array('a', 'b', 'b', 'd');
$new_array = array();
$keys = array_keys($array);
for($i=0; $i<count($array); $i++) {
$new_array[$i+1] = $array[$i];
}
print_r($new_array);
来源:https://stackoverflow.com/questions/13148506/php-explode-and-force-array-keys-to-start-from-1-and-not-0