问题
So I want the buttons to change style when mouse is down, and return to previous when it goes up. I have this code:
$('#divMenu > #menu li a').mousedown(function(){
$(this).css({
'font-size': '25px',
'color': 'red'
});
}).mouseup(function(){
$(this).css({
'font-size': '30px',
'color': 'black'
});
});
The problem is, that when I have mouse down, but take it away of my object and not release immediately, font size and color stays 25px and red. What should I do to pass that?
EDIT: JsFiddle here: http://jsfiddle.net/h64Uz/
回答1:
You need to use a mouseout as well.
$('#divMenu > #menu li a').mousedown(function(){
$(this).css({
'font-size': '25px',
'color': 'red'
});
}).mouseup(function(){
$(this).css({
'font-size': '30px',
'color': 'black'
});
}).mouseout(function(){
$(this).css({
'font-size': '30px',
'color': 'black'
});
});
Your event code sets the css when the mouse is clicked. Once you move away it can't register a mouseup. But on leaving it will register a mouseout event.
回答2:
jQuery has a mouseleave()
event you can use to supplement the existing code:
回答3:
This should work (assuming you are using jQuery
version 1.7 or above):
$('#divMenu > #menu li a').on("mousedown", function () {
$(this).css({
'font-size': '25px',
'color': 'red'
});
}).on("mouseup mouseout", function () {
$(this).css({
'font-size': '30px',
'color': 'black'
});
});
来源:https://stackoverflow.com/questions/14207927/mouseup-and-mousedown