How can I convert a string into exact number in Scheme Lisp?

问题

For example, I have this string: "6119726089.12814713"

If I do (string->number "6119726089.12814713") - using the SISC implementation the result is 6.119726089128147e9 - and in Guile implementation is 6119726089.128147 but I would like an exact number, like: 611972608912814713/100000000 without loss precision.

I'd like a function like (string->exact) or something like this.

NOTE: please fix my non-native English and remove this message. Thanks.

回答1:

Use (string->number "#e6119726089.12814713") to parse the number as exact. This works for at least Racket and Guile. It may not work correctly on other Scheme implementations, however; they are at liberty to parse as inexact first, then convert.

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Here's a portable implementation of the string->exact function that the OP asked for. I've manually tested it with a range of inputs, but you should do your own testing to ensure it fits your needs:

(define (string->exact str)
  (define zero (char->integer #\0))
  (let loop ((result #f)
             (factor 1)
             (seen-dot? #f)
             (digits (string->list str)))
    (if (null? digits)
        (and result (/ result factor))
        (let ((cur (car digits))
              (next (cdr digits)))
          (cond ((and (not result) (not seen-dot?) (char=? cur #\-))
                 (loop result (- factor) seen-dot? next))
                ((and (not seen-dot?) (char=? cur #\.))
                 (loop result factor #t next))
                ((char<=? #\0 cur #\9)
                 (loop (+ (* (or result 0) 10) (- (char->integer cur) zero))
                       (if seen-dot? (* factor 10) factor)
                       seen-dot? next))
                (else #f))))))

来源：https://stackoverflow.com/questions/23027030/how-can-i-convert-a-string-into-exact-number-in-scheme-lisp