问题
I'm trying to create a jersey client to hit a server with multipart request.
I have the file to upload as a java.io.ByteArrayOutputStream
type stream.
I searched for the error and came across this question here and this answer here
and added
register(MultiPartFeature.class)
while creating a Client
, but to no effect.
I probably just need a nudge in the right direction. Thanks!
I'm not using Maven or anything.
Relevant part from my java
file is:
FormDataMultiPart multiPart = new FormDataMultiPart();
FormDataContentDisposition.FormDataContentDispositionBuilder dispositionBuilder = FormDataContentDisposition
.name("file");
dispositionBuilder.fileName("file.zip");
FormDataContentDisposition formDataContentDisposition = dispositionBuilder.build();
/*
* byteArrayOutputStream is of type java.io.ByteArrayOutputStream
* and contains the file I wish to upload.
*/
multiPart.bodyPart(
new FormDataBodyPart("file", byteArrayOutputStream, MediaType.APPLICATION_OCTET_STREAM_TYPE)
.contentDisposition(formDataContentDisposition));
Entity < FormDataMultiPart > entity = Entity.entity(multiPart, MediaType.MULTIPART_FORM_DATA_TYPE);
Client client = ClientBuilder.newClient(new ClientConfig().register(MultiPartFeature.class));
WebTarget webTarget = client.target("http://localhost:3000/path/to/service");
// send request
Invocation.Builder invocationBuilder = webTarget.request();
Response response = invocationBuilder.post(entity);
return response;
Relevant part from web.xml
is:
<servlet>
<servlet-name>Jersey Web Application</servlet-name>
<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>jersey.config.server.provider.packages</param-name>
<param-value>com.example</param-value>
</init-param>
<init-param>
<param-name>jersey.config.server.provider.classnames</param-name>
<param-value>org.glassfish.jersey.filter.LoggingFilter;org.glassfish.jersey.media.multipart.MultiPartFeature</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
I get this following error while trying to run it inside Eclipse on a Apache Tomcat 8.5 runtime server.
SEVERE: Servlet.service() for servlet [Jersey Web Application] in context with path [/TestRest] threw exception [javax.ws.rs.ProcessingException: No available MessageBodyWriter for class "class java.io.ByteArrayOutputStream" and media type "multipart/form-data".] with root cause
java.lang.IllegalArgumentException: No available MessageBodyWriter for class "class java.io.ByteArrayOutputStream" and media type "multipart/form-data".
at org.glassfish.jersey.media.multipart.internal.MultiPartWriter.writeTo(MultiPartWriter.java:229)
at org.glassfish.jersey.media.multipart.internal.MultiPartWriter.writeTo(MultiPartWriter.java:79)
at org.glassfish.jersey.message.internal.WriterInterceptorExecutor$TerminalWriterInterceptor.invokeWriteTo(WriterInterceptorExecutor.java:265)
at org.glassfish.jersey.message.internal.WriterInterceptorExecutor$TerminalWriterInterceptor.aroundWriteTo(WriterInterceptorExecutor.java:250)
at org.glassfish.jersey.message.internal.WriterInterceptorExecutor.proceed(WriterInterceptorExecutor.java:162)
at org.glassfish.jersey.message.internal.MessageBodyFactory.writeTo(MessageBodyFactory.java:1130)
回答1:
There's no MessageBodyWriter
that handles OutputStream
. Use an InputStream
instead
回答2:
Ok , you register MultiPartFeature.class
Client client = ClientBuilder.newClient(new ClientConfig().register(MultiPartFeature.class));
but you have to handle and register response type, Suppose you upload a file and response's media type is json, so you must add a register like that;
Client client = ClientBuilder.newClient(new ClientConfig().register(MultiPartFeature.class).register(JacksonFeature.class));
来源:https://stackoverflow.com/questions/42794502/no-available-messagebodywriter-for-media-type-multipart-form-data