问题
I have a legacy code that calls class TiffFile(file)
. What is the python3 way to call it?
I tried to replace following in python2:
class TiffFile(file):
def __init__(self, path):
file.__init__(self, path, 'r+b')
By this in python3:
class TiffFile(RawIOBase):
def __init__(self, path):
super(TiffFile, self).__init__(path, 'r+b')
But now I am getting TypeError: object.__init__() takes no parameters
回答1:
RawIOBase.__init__ does not take any arguments, that is where you error is.
Your TiffFile
implementation also inherits file which is not a a class, but a constructor function, so your Python 2 implementation is non-idiomatic, and someone could even claim it is wrong-ish. You should use open
instead of file
, and in a class context you should use an io
module class for input and output.
You can use open to return a file object for use as you would use file
in Python 2.7 or you can use io.FileIO
in both Python 2 and Python 3 for accessing file streams, like you would do with open
.
So your implementation would be more like:
import io
class TiffFile(io.FileIO):
def __init__(self, name, mode='r+b', *args, **kwargs):
super(TiffFile, self).__init__(name, mode, *args, **kwargs)
This should work in all currently supported Python versions and allow you the same interface as your old implementation while being more correct and portable.
Are you actually using r+b
for opening the file in read-write-binary mode on Windows? You should probably be using rb
mode if you are not writing into the file, but just reading the TIFF data. rb
would open the file in binary mode for reading only. The appended +
sets the file to open in read-write mode.
来源:https://stackoverflow.com/questions/47838405/porting-a-sub-class-of-python2-file-class-to-python3