问题
So I'm trying some code out to convert numbers into strings. However, I noticed that in certain cases it does not preserve the last two decimal places. For instance I type 1.01 and 1.04 for addition and I get back 2.04. If I type just 1.05 it preserves the number and returns it exactly. I get whats going on things are being rounded. I don't know how to prevent it from being rounded though. Should I just consider sending (1.01+1.04) to self as only one input?
Warning! I haven't tried this yet so don't know if its supported:
user_input = (1.04+1.01) #entry from user
user_input = gets.to_f
user_input.to_test_string
What I have so far:
class Float
def to_test_string
cents = self % 1
dollars = self - cents
cents = cents * 100
text = "#{dollars.to_i.en.numwords} dollars and #{cents.to_i.en.numwords} cents"
puts text
text
end
end
puts "Enter two great floating point numbers for adding"
puts "First number"
c = gets.to_f
puts "Second number"
d = gets.to_f
e = c+d
puts e.to_test_string
puts "Enter a great floating number! Example 10.34"
a = gets.to_f
puts a.to_test_string
Thanks for the help! Post some code up so I can try!
回答1:
First of all: never use float for money — Use Float or Decimal for Accounting Application Dollar Amount?
irb> x = 1.01 + 1.04
=> 2.05
irb> y = x % 1
=> 0.04999999999999982
irb> (y * 100).to_i
=> 4
But if want it VERYVERYVERY much:
irb> (y * 100).round.to_i
=> 5
回答2:
$ python
Python 2.6.2 (release26-maint, Apr 19 2009, 01:56:41)
[GCC 4.3.3] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> 1.04+1.01
2.0499999999999998
Read this: What Every Computer Scientist Should Know About Floating-Point Arithmetic
Also, what Nakilon said.
回答3:
This is not a problem with ruby, nor your code (although you need to get rid of .en.numwords); it is a problem with the binary floating point representation.
You should use a Fixnum or Bignum to represent the currency.
eg.
class Currency
def initialize str
unless str =~ /([0-9]+)\.([0-9]{2})/
raise 'invalid currency string'
end
@cents = $1.to_i * 100 + $2.to_i
end
end
来源:https://stackoverflow.com/questions/4119916/how-do-i-preserve-my-float-number-in-ruby