What does this array-style destructuring on a function do in ES6?

问题

I read through the redux-actions tutorial, and am confused by their use of (what I believe to be) destructuring. Below is an example (increment & decrement are both functions returned by the createAction function).

const { createAction, handleActions } = window.ReduxActions;

const reducer = handleActions(
  {
    [increment]: state => ({ ...state, counter: state.counter + 1 }),
    [decrement]: state => ({ ...state, counter: state.counter - 1 })
  },
  defaultState
);

Here's another example of this being used:

const { createActions, handleActions, combineActions } = window.ReduxActions;

const reducer = handleActions(
  {
    [combineActions(increment, decrement)]: (
      state,
      { payload: { amount } }
    ) => {
      return { ...state, counter: state.counter + amount };
    }
  },
  defaultState
);

Can somebody explain what's happening in those lines? In simplified terms, I just see {[function]: () => ({})}, and don't understand what this does.

回答1:

That's indeed a computed property name, but with a twist - a function is used as a key, not a string.

It might look confusing until you remember that each function can be safely cast to string - the result is that function's source code. And that's exactly what happens here:

function x() {}
const obj = { [x]: 42 };
console.log( obj[x] ); // 42
console.log( obj[x.toString()] ); // 42, key is the same actually
console.log( Object.keys(obj) );  // ["function x() {}"]

The advantage of such approach is that you don't need to create additional keys - if you have a function reference, you already have one. In fact, you don't even have to have a reference - it's enough to have a function with the same source:

const one = () => '';
const two = () => '';
console.log(one === two); // false apparently 
const fatArrObj = { [one]: 42 } 
fatArrObj[two]; // 42, take that Oxford scholars!!

The disadvantage is that function is cast to string each time it's used as key - a (supposedly minor) performance hit.

To add some fun, this is valid object literal:

{ 
   [null]: null, // access either with [null] or ['null']
   [undefined]: undefined, 
   [{ toString: () => 42 }]: 42 // access with, you guess it, 42 (or '42')
}

... and this one might go into book of weird interview questions:

const increment = (() => { let x = 0; return () => ++x })();
const movingTarget = { toString: increment };
const weirdObjectLiteral = { [movingTarget]: 42 };
console.log( weirdObjectLiteral[movingTarget] ); // undefined

来源：https://stackoverflow.com/questions/52123007/what-does-this-array-style-destructuring-on-a-function-do-in-es6

标签

javascript

ecmascript-6

destructuring

redux-actions