问题
I am looking for a way to generate a sequence for a column with names of cities grouped by an ID. What is crucial is that when a name of a city is repeated (within the group) a new sequence has to start. A new sequence should also start in case of a new ID.
EDIT:
The question how to create the above mentioned sequence has been solved. To help select the row with the highest sequence number later on, I am looking for a way to add a new column to the data frame that shows for each record, per sequence, per ID the highest number of each sequence.
Here is an example of what I want to achieve, based on a simplified version of my data frame:
ID City Sequence Highest_number
1 Nijmegen 1 2
1 Nijmegen 2 2
1 Arnhem 1 2
1 Arnhem 2 2
1 Nijmegen 1 1
1 Arnhem 1 3
1 Arnhem 2 3
1 Arnhem 3 3
1 Nijmegen 1 1
2 Nijmegen 1 1
2 Utrecht 1 1
2 Amsterdam 1 2
2 Amsterdam 2 2
2 Utrecht 1 4
2 Utrecht 2 4
2 Utrecht 3 4
2 Utrecht 4 4
mydf <- data.frame(ID = c(1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2),
City = c("Nijmegen", "Nijmegen", "Arnhem", "Arnhem", "Nijmegen",
"Arnhem", "Arnhem","Arnhem", "Nijmegen", "Nijmegen", "Utrecht",
"Amsterdam", "Amsterdam", "Utrecht", "Utrecht", "Utrecht", "Utrecht"))
回答1:
Construct a 'run-length encoding' and use that to generate the sequences
rle <- rle(as.character(mydf$City))
mydf$Sequence <- unlist(lapply(rle$length, seq_len))
For the updated question, where two columns form the key, paste the columns together with a unique symbol and compute with that
rle <- rle(paste(mydf$ID, mydf$City, sep = "\r"))
mydf$Sequence <- unlist(lapply(rle$length, seq_len))
This will be 'fast', especially compared to a for loop.
回答2:
A good old for loop does the trick
mydf$Sequence <- NA
for(i in seq_len(nrow(mydf))) {
if (i == 1 || (mydf$City[i] != mydf$City[i-1]) || (mydf$ID[i] != mydf$ID[i-1]))
mydf$Sequence[i] <- 1
else
mydf$Sequence[i] <- mydf$Sequence[i-1] + 1
}
来源:https://stackoverflow.com/questions/48298647/generate-sequence-and-starting-over-in-case-of-a-recurrence-and-add-new-column