How to view session details in php using firebug?

问题

I'm trying to figure out I how can do something like:

console.log('<?php print_r($_SESSION); ?>'); 

To see the results in the console.

console.log('<?php echo serialize($_SESSION); ?>');

does not work either. Is there a way for me to echo the session information in firebug or inspect element in chrome for testing purposes?

回答1:

You could try this :

<script>
    console.log(<?php echo json_encode($_SESSION, JSON_HEX_TAG); ?>);
</script>

No quotes are required. See as well Firebug and Logging.

---

[edit, May 2014] Updated the code to be safe against XSS attacks. Always pass JSON_HEX_TAG to json_encode if you're embedding in HTML, or an attacker could inject code into the DOM by having you encode a string like:

</script><script>alert('Hello!');

回答2:

It is not possible to view the session details using fire bug.

来源：https://stackoverflow.com/questions/8674220/how-to-view-session-details-in-php-using-firebug