问题
Similarly to How do I remove code duplication between similar const and non-const member functions?, I want to remove the code duplication between nearly identical member functions, except for ref qualifiers.
Let's say I have a class that's something like this:
class MyStringBuilder
{
std::string member;
public:
// Other functions
std::string create() const& {
// Some work
std::string result = member;
// More work
return result;
}
std::string create() && {
// Some work
std::string result = std::move(member);
// More work
return result;
}
};
It's not inconceivable that we would want to do this for a builder object, as it saves a copy if we are done with the MyStringBuilder
.
Except for where members are used, the code between the const&
version and &&
version are identical. The only difference between the two functions is that the &&
version std::move
s any members whenever they are referenced.
How can I avoid this code duplication?
回答1:
One thing you can do is you can implement the logic in a non-member function and take the type of *this
as a template parameter:
class MyStringBuilder
{
std::string member;
template<typename Self>
static std::string create_impl(Self&& self) {
// Some work
std::string result = std::forward<Self>(self).member;
// More work
return result;
}
public:
// Other functions
std::string create() const& {
return create_impl(*this);
}
std::string create() && {
return create_impl(std::move(*this));
}
};
来源:https://stackoverflow.com/questions/44644310/how-do-i-remove-code-duplication-between-similar-ref-qualified-member-functions