问题
In the py.test docs it describes declaring factory methods as fixtures, like-so:
@pytest.fixture
def make_foo():
def __make_foo(name):
foo = Foo()
foo.name = name
return foo
return __make_foo
What are the benefits/tradeoffs of doing this over just defining a make_foo function and using that? I don't understand why it is a fixture.
回答1:
Actually, the most important advantage is being able to use other fixtures, and make the dependency injection of pytest work for you. The other advantage is allowing you to pass parameters to the factory, which would have to be static in a normal fixture.
Look at this example:
@pytest.fixture
def mocked_server():
with mock.patch('something'):
yield MyServer()
@pytest.fixture
def connected_client(mocked_server):
client = Client()
client.connect_to(mocked_server, local_port=123) # local_port must be static
return client
You could now write a test that gets a connected_client
, but you can't change the port.
What if you need a test with multiple clients? You can't either.
If you now write:
@pytest.fixture
def connect_client(mocked_server):
def __connect(local_port):
client = Client()
client.connect_to(mocked_server, local_port)
return client
return __connect
You can now write a test receiving a connect_client
factory, and call it to get an initialized client, in any port, and how many times you want!
回答2:
One example might be a session-level fixture, e.g.:
@pytest.fixture(scope="session")
def make_foo():
def __make_foo(name):
foo = Foo()
foo.name = name
return foo
return __make_foo
This way, Pytest will ensure that only one instance of the factory exists for the duration of your tests. This example in particular perhaps doesn't gain much from this, but if the outer function does a lot of processing, such as reading from a file or initialising data structures, then this can save you a lot of time overall.
回答3:
see below code, this gives ans to your questions..
import pytest
@pytest.fixture
def make_foo():
def __make_foo(name):
print(name)
return __make_foo
def test_a(make_foo):
make_foo('abc')
def test_b(make_foo):
make_foo('def')
The output is shown below ::
tmp3.py::test_a abc
PASSED
tmp3.py::test_b def
PASSED
basically you can pass the arguments in factory fixture and can use according to your requirement.
来源:https://stackoverflow.com/questions/51663326/why-would-a-pytest-factory-as-fixture-be-used-over-a-factory-function