问题
Lets say I have an enum with bitflag options larger than the amount of bits in a standard data type:
enum flag_t {
FLAG_1 = 0x1,
FLAG_2 = 0x2,
...
FLAG_130 = 0x400000000000000000000000000000000,
};
This is impossible for several reasons. Enums are max size of 128 bits (in C/gcc on my system from experimentation), single variables are also of max size 128 bits etc.
In C you can't perform bitwise operations on arrays, though in C++ I suppose you could overload bitwise operators to do the job with a loop.
Is there any way in C other than manually remembering which flags go where to have this work for large numbers?
回答1:
This is exactly what bit-fields are for.
In C, it's possible to define the following data layout :
struct flag_t
{
unsigned int flag1 : 1;
unsigned int flag2 : 1;
unsigned int flag3 : 1;
(...)
unsigned int flag130 : 1;
(...)
unsigned int flag1204 : 1; // for fun
};
In this example, all flags occupy just one bit. An obvious advantage is the unlimited number of flags. Another great advantage is that you are no longer limited to single-bit flags, you could have some multi-value flags merged in the middle.
But most importantly, testing and attribution would be a bit different, and probably simplified, as far as unit operations are concerned : you no longer need to do any masking, just access the flag directly by naming it. And by the way, use the opportunity to give these flags more comprehensive names :)
回答2:
Instead of trying to assign absurdly large numbers to an enum so you can have a hundreds-of-bits-wide bitfield, let the compiler assign a normal zero-based sequence of numbers to your flag names, and simulate a wide bitfield using an array of unsigned char. You can have a 1024-bit bitfield using unsigned char bits[128]
, and write get_flag()
and set_flag()
accessor functions to mask the minor amount of extra work involved.
However, a far better piece of advice would be to look at your design again, and ask yourself "Why do I need over a hundred different flags?". It seems to me that what you really need is a redesign.
回答3:
In this answer to a question related to bitflags, Bit Manipulation and Flags, I provided an example of using an unsigned char
array that is an approach for very large sets of bitflags which I am moving to this posting.
This source example provides the following:
- a set of Preprocessor defines for the bitflag values
- a set of Preprocessor macros to manipulate bits
- a couple of functions to implement bitwise operations on the arrays
The general approach for this is as follows:
- create a set of defines for the flags which specify an array offset and a bit pattern
- create a typedef for an
unsigned char
array of the proper size - create a set of functions that implement the bitwise logical operations
The Specifics from the Answer with a Few Improvements and More Exposition
Use a set of C Preprocessor defines to create a set of bitflags to be used with the array. These bitflag defines specify an offset within the unsigned char
array along with the bit to manipulate.
The defines in this example are 16 bit values in which the upper byte contains the array offset and the lower byte contains the bit flag(s) for the byte of the unsigned char
array whose offset is in the upper byte. Using this technique you can have arrays up to 256 elements, 256 * 8 or 2,048 bitflags, or by going from a 16 bit define to a 32 bit long
you could have much more. (In the comments below bit 0 means least significant bit of a byte and bit 7 means most significant bite of a byte).
#define ITEM_FLG_01 0x0001 // array offset 0, bit 0
#define ITEM_FLG_02 0x0002 // array offset 0, bit 1
#define ITEM_FLG_03 0x0101 // array offset 1, bit 0
#define ITEM_FLG_04 0x0102 // array offset 1, bit 1
#define ITEM_FLG_05 0x0201 // array offset 2, bit 0
#define ITEM_FLG_06 0x0202 // array offset 2, bit 1
#define ITEM_FLG_07 0x0301 // array offset 3, bit 0
#define ITEM_FLG_08 0x0302 // array offset 3, bit 1
#define ITEM_FLG_10 0x0908 // array offset 9, bit 7
Next you have a set of macros to set and unset the bits along with a typedef
to make it a bit easier to use. Unfortunately using a typedef
with C does not provide you better type checking from the compiler but it does make it easier to use. These macros do no checking of their arguments so you might feel safer using regular functions instead.
#define SET_BIT(p,b) (*((p) + (((b) >> 8) & 0xf)) |= (b) & 0xf)
#define TOG_BIT(p,b) (*((p) + (((b) >> 8) & 0xf)) ^= (b) & 0xf)
#define CLR_BIT(p,b) (*((p) + (((b) >> 8) & 0xf)) &= ~ ((b) & 0xf))
#define TST_BIT(p,b) (*((p) + (((b) >> 8) & 0xf)) & ((b) & 0xf))
typedef unsigned char BitSet[10];
An example of using this basic framework is as follows.
BitSet uchR = { 0 };
int bValue;
SET_BIT(uchR, ITEM_FLG_01);
bValue = TST_BIT(uchR, ITEM_FLG_01);
SET_BIT(uchR, ITEM_FLG_03);
TOG_BIT(uchR, ITEM_FLG_03);
TOG_BIT(uchR, ITEM_FLG_04);
CLR_BIT(uchR, ITEM_FLG_05);
CLR_BIT(uchR, ITEM_FLG_01);
Next you can introduce a set of utility functions to do some of the bitwise operations we want to support. These bitwise operations would be analogous to the built in C operators such as bitwise Or (|
) or bitwise And (&
). These functions use the built in C operators to perform the designated operator on all array elements.
These particular examples of the utility functions modify one of the sets of bitflags provided. However if that is a problem, you can modify the functions to accept three arguments, one being for the result of the operation and the other two for the two sets of bitflags to use in the operation.
void AndBits(BitSet s1, const BitSet s2)
{
size_t nLen = sizeof(BitSet);
for (; nLen > 0; nLen--) {
*s1++ &= *s2++;
}
}
void OrBits(BitSet s1, const BitSet s2)
{
size_t nLen = sizeof(BitSet);
for (; nLen > 0; nLen--) {
*s1++ |= *s2++;
}
}
void XorBits(BitSet s1, const BitSet s2)
{
size_t nLen = sizeof(BitSet);
for (; nLen > 0; nLen--) {
*s1++ ^= *s2++;
}
}
If you need more than one size of a bitflags type using this approach then the most flexible approach to eliminate the typedef
and just use straight unsigned char
arrays of various sizes. This change would entail modifying the interface of the utility functions replacing BitSet
with unsigned char
pointer and unsigned char
arrays where bitflag variables are defined. Along with the unsigned char
pointers, you would also need to specify a length for the arrays.
You may also consider an approach similar to what is being done for text strings in Is concatenating arbitrary number of strings with nested function calls in C undefined behavior?.
来源:https://stackoverflow.com/questions/16421485/creating-bitflag-variables-with-large-amounts-of-flags-or-how-to-create-large-bi