Java: Issue combining Generics, Inner class, and “implements”

别来无恙 提交于 2019-12-07 13:24:52

问题


I am having an issue combining generics, implements, and inner classes. I am creating a LinkedBinaryHeap class which contains an inner class. This inner class is the generic HeapNode which extends the generic Node class I created; it just adds a variable and methods for a key/priority.

In LinkedBinaryHeap I create a generic LinkedList to store HeapNodes. I am assuming the generic data being stored extends Comparable class.

Here is a layout of what stores what:

BinaryHeap->LinkedList(Nodes)->HeapNode(extends Node)->DATA,KEY

My issue is that when declaring the LinkedList:

LinkedList<HeapNode> heap;

eclipse underlines HeapNode and gives me the error:

Bound mismatch: The type LinkedBinaryHeap.HeapNode is not a 
valid substitute for the bounded parameter > 
of the type LinkedList

I think the error is telling me that HeapNode must implement the Comparable, however my Node class implements Comparable, so that is taken care of, correct?

I have tried all sorts of different things, but nothing seems to work, the below code is the closest I came. Note that I have tried leaving implements Comparable Node<T> off the HeapNode inner class, and it changes nothing.

Code:

LinkedBinaryHeap.java:

public class LinkedBinaryHeap<E extends Comparable<E>> {
    private LinkedList<HeapNode> heap;

    public LinkedBinaryHeap(){
        heap = new LinkedList<HeapNode>();
    }

    /* INNER CLASS DECLARATION. */
    private class HeapNode extends Node<E> implements Comparable<Node<E>>{
        int key;
        public HeapNode(int key, E data){
            super(data);
            this.key = key;
        }

        public int getKey(){
            return key;
        }

        public void setKey(int key){
            this.key = key;
        }
    }
}

Node.java:

public class Node<T extends Comparable<T>> implements Comparable<Node<T>>{
    protected T data;
    protected Node<T> next;
    protected Node<T> previous;

    public Node(T data){
        next = null;
        previous = null;
        this.data = data;
    }   

    /* Some other methods left out here. */

    public int compareTo(Node<T> node) {
        return data.compareTo(node.getData());
    }
}

LinkedList.java:

public class LinkedList<T extends Comparable<T>> implements Comparable<LinkedList<T>>{
    private Node<T> head;
    private Node<T> tail;
    private int size;

    public LinkedList(){
        head = null;
        tail = null;
        size = 0;
    }

    /* Other methods left out. */

    public int compareTo(LinkedList<T> list){
        // does stuff.
    }
}

回答1:


As per your definitions:

  1. HeapNode is a subtype of Node<E> but implements Comparable<Node<E>>
  2. LinkedList requires a type argument such that T implements Comparable<T>
  3. i.e. a LinkedList<HeapNode> requires that HeapNode implements Comparable<HeapNode>
  4. which it does not (from (1), above, it implements Comparable<Node<E>>)

So the two are not compatible.

You need, in LinkedList, to express the node type as a type parameter, bounded appropriately, and the node type's component type parameter as well, also bounded appropriately:

public class LinkedList<N extends Node<E>, 
                        E extends Comparable<E>> 
  implements Comparable<LinkedList<N, E>>{
  private N head;
  private N tail;
  private int size;
  ...

Now your LinkedBinaryHeap needs to adjust it's use of LinkedList:

public class LinkedBinaryHeap<E extends Comparable<E>> {
  private LinkedList<HeapNode, E> heap;

  public LinkedBinaryHeap(){
      heap = new LinkedList<HeapNode, E>();
  }

That should now compile. Whether it achieves your goals of comparing everything to everything else is harder to say!




回答2:


LinkedList requires that T implements Comparable. HeapNode implements Comparable<Node<E>>. HeapNode != Node so it doesn't satisfy the type bound. Change LinkedList's declaration to T extends Comparable<? super T>. This is fine, type-wise: HeapNode is declaring that it can compare itself with any Node or subtype of Node. Of course, this means that HeapNode needs to override compareTo, but you're kind of stuck there, what with Node already implementing Comparable.

Edit: as comments point out, this answer is wrong, and not worth fixing because there's a right answer. Let it stay for posterity as a lesson in...something. How I'm not as knowledgeable on generics as I'd like to be, maybe.



来源:https://stackoverflow.com/questions/28653444/java-issue-combining-generics-inner-class-and-implements

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