Is this possible to reproduce this lattice plot with ggplot2?
library(latticeExtra)
data(mtcars)
x <- t(as.matrix(scale(mtcars)))
dd.row <- as.dendrogram(hclust(dist(x)))
row.ord <- order.dendrogram(dd.row)
dd.col <- as.dendrogram(hclust(dist(t(x))))
col.ord <- order.dendrogram(dd.col)
library(lattice)
levelplot(x[row.ord, col.ord],
aspect = "fill",
scales = list(x = list(rot = 90)),
colorkey = list(space = "left"),
legend =
list(right =
list(fun = dendrogramGrob,
args =
list(x = dd.col, ord = col.ord,
side = "right",
size = 10)),
top =
list(fun = dendrogramGrob,
args =
list(x = dd.row,
side = "top",
size = 10))))
EDIT
From 8 August 2011 the ggdendro
package is available on CRAN
Note also that the dendrogram extraction function is now called dendro_data
instead of cluster_data
Yes, it is. But for the time being you will have to jump through a few hoops:
- Install the
ggdendro
package (available from CRAN). This package will extract the cluster information from several types of cluster methods (includingHclust
anddendrogram
) with the express purpose of plotting inggplot
. - Use grid graphics to create viewports and align three different plots.
The code:
First load the libraries and set up the data for ggplot:
library(ggplot2)
library(reshape2)
library(ggdendro)
data(mtcars)
x <- as.matrix(scale(mtcars))
dd.col <- as.dendrogram(hclust(dist(x)))
col.ord <- order.dendrogram(dd.col)
dd.row <- as.dendrogram(hclust(dist(t(x))))
row.ord <- order.dendrogram(dd.row)
xx <- scale(mtcars)[col.ord, row.ord]
xx_names <- attr(xx, "dimnames")
df <- as.data.frame(xx)
colnames(df) <- xx_names[[2]]
df$car <- xx_names[[1]]
df$car <- with(df, factor(car, levels=car, ordered=TRUE))
mdf <- melt(df, id.vars="car")
Extract dendrogram data and create the plots
ddata_x <- dendro_data(dd.row)
ddata_y <- dendro_data(dd.col)
### Set up a blank theme
theme_none <- theme(
panel.grid.major = element_blank(),
panel.grid.minor = element_blank(),
panel.background = element_blank(),
axis.title.x = element_text(colour=NA),
axis.title.y = element_blank(),
axis.text.x = element_blank(),
axis.text.y = element_blank(),
axis.line = element_blank()
#axis.ticks.length = element_blank()
)
### Create plot components ###
# Heatmap
p1 <- ggplot(mdf, aes(x=variable, y=car)) +
geom_tile(aes(fill=value)) + scale_fill_gradient2()
# Dendrogram 1
p2 <- ggplot(segment(ddata_x)) +
geom_segment(aes(x=x, y=y, xend=xend, yend=yend)) +
theme_none + theme(axis.title.x=element_blank())
# Dendrogram 2
p3 <- ggplot(segment(ddata_y)) +
geom_segment(aes(x=x, y=y, xend=xend, yend=yend)) +
coord_flip() + theme_none
Use grid graphics and some manual alignment to position the three plots on the page
### Draw graphic ###
grid.newpage()
print(p1, vp=viewport(0.8, 0.8, x=0.4, y=0.4))
print(p2, vp=viewport(0.52, 0.2, x=0.45, y=0.9))
print(p3, vp=viewport(0.2, 0.8, x=0.9, y=0.4))
As Ben says, everything is possible. Some work to support dendrograms has been done. Andrie de Vries has made a fortify method of tree objects. However, the resulting graphic is not pretty as you can see.
The tile would be easy to do. For the dendrogram I would inspect plot.dendrogram
(using getAnywhere
) to see how the coordinates for the segments are calculated. Extract those coordinates and use geom_segment to plot the dendrogram. Then use viewports to plot the tiles and the dendrogram together. Sorry I can't give a example, it's a lot of work and it's too late.
I hope this helps
Cheers
Doubtful. I do not see any functions in the Index for ggplot2 that would suggest support for dendrograms, and when this blogger put together a set of translations of the illustrations in Sarkar's Lattice book, he was unable to get a ggplot dendrogram legend:
These links provide a solution for heatmaps with dendrograms in ggplot2:
https://gist.github.com/chr1swallace/4672065
https://github.com/chr1swallace/random-functions/blob/master/R/ggplot-heatmap.R
and also this one:
来源:https://stackoverflow.com/questions/6673162/reproducing-lattice-dendrogram-graph-with-ggplot2