问题
I am getting an error 'Attempt to mutate immutable object with appendString:'
and my code is
NSMutableString *resultString= [[NSMutableString alloc]init];
for (NSMutableString *s in self.ArrayValue)
{
[resultString appendString:s];
NSLog(resultString);
}
ArrayValue is NSMutableArray.
I am not able to understand where is the problem
thank you in advance
回答1:
As posted, the code you have will not give you the error you describe. Probably, somewhere between allocating resultString and the for loop, you are overwriting it with a normal NSSring.
回答2:
Just do have like this:
It works for me...
NSMutableString *resultString= [[NSMutableString alloc]init];
NSMutableArray *ArrayValue=[[NSMutableArray alloc]init];
[ArrayValue addObject:@"One"];
[ArrayValue addObject:@"Two"];
[ArrayValue addObject:@"Three"];
for (NSMutableString *s in ArrayValue)
{
[resultString appendString:s];
NSLog(@"%@",resultString);------->You should use %@ to print the string otherwise will show your warning.
}
O/P on Console:
2011-03-08 19:13:02.243 iPadMables[4557:207] One
2011-03-08 19:13:06.224 iPadMables[4557:207] OneTwo
2011-03-08 19:13:09.388 iPadMables[4557:207] OneTwoThree
回答3:
ArrayValue = [NSMutableArray arrayWithObjects:@"b",@"o",@"n",nil];
NSMutableString *resultString= [[NSMutableString alloc]init];
for (NSMutableString *s in self.ArrayValue)
{
[resultString appendString:s];
NSLog(resultString);
}
works for me..
来源:https://stackoverflow.com/questions/5233178/error-attempt-to-mutate-immutable-object-with-appendstring