问题
I am learning Python and I have been tasked with:
- adding "file_" to the beginning of each name in a directory
- changing the extension (directory contains 4 different types currently: .py, .TEXT, .rtf, .text)
I have many files, all with different names, each 7 characters long. I was able to change the extensions but it feels very clunky. I am positive there is a cleaner way to write the following (but its functioning, so no complaints on that note):
import os, sys
path = 'C:/Users/dana/Desktop/text_files_2/'
for filename in os.listdir(path):
if filename.endswith('.rtf'):
newname = filename.replace('.rtf', '.txt')
os.rename(filename, newname)
elif filename.endswith('.py'):
newname = filename.replace('.py', '.txt')
os.rename(filename, newname)
elif filename.endswith('.TEXT'):
newname = filename.replace('.TEXT', '.txt')
os.rename(filename, newname)
elif filename.endswith('.text'):
newname = filename.replace('.text', '.txt')
os.rename(filename, newname)
I do still have a bit of a problem:
- the script currently must be inside my directory for it to run.
I can not figure out how to add "file_" to the start of each of the filenames [you would think that would be the easy part]. I have tried declaring newname as
newname = 'file_' + str(filename)
it then states filename is undefined.
Any assistance on my two existing issues would be greatly appreciated.
回答1:
The basic idea would be first get the file extension part and the real file name part, then put the filename into a new string.
os.path.splitext(p)
method will help to get the file extensions, for example: os.path.splitext('hello.world.aaa.txt')
will return ['hello.world.aaa', '.txt']
, it will ignore the leading dots.
So in this case, it can be done like this:
import os
import sys
path = 'C:/Users/dana/Desktop/text_files_2/'
for filename in os.listdir(path):
filename_splitext = os.path.splitext(filename)
if filename_splitext[1] in ['.rtf', '.py', '.TEXT', '.text']:
os.rename(os.path.join(path, filename),
os.path.join(path, 'file_' + filename_splitext[0] + '.txt'))
回答2:
Supply the full path name with os.path.join()
:
os.rename(os.path.join(path, filename), os.path.join(name, newname))
and you can run your program from any directory.
You can further simply your program:
extensions = ['.rtf', '.py', '.TEXT', '.text']
for extension in extensions:
if filename.endswith(extension):
newname = filename.replace(extension, '.txt')
os.rename(os.path.join(path, filename), os.path.join(path, newname))
break
All the other elif
statements are not needed anymore.
回答3:
import glob, os
path = 'test/'# your path
extensions = ['.rtf', '.py', '.TEXT', '.text']
for file in glob.glob(os.path.join(path, '*.*')):
file_path, extension = os.path.splitext(file)
if extension in extensions:
new_file_name = '{0}.txt'.format(
os.path.basename(file_path)
)
if not new_file_name.startswith('file_'): # check if file allready has 'file_' at beginning
new_file_name = 'file_{0}'.format( # if not add
new_file_name
)
new_file = os.path.join(
os.path.dirname(file_path),
new_file_name
)
os.rename(file, new_file)
file_path, extension = os.path.splitext(file)
getting file path without extension and extension f.e('dir_name/file_name_without_extension','.extension')
os.path.dirname(file_path)
getting directory f.e if file_path isdir1/dir2/file.ext
result will be'dir1/dir2'
os.path.basename(file_path)
getting file name without extension
回答4:
import os, sys
path = 'data' // Initial path
def changeFileName( path, oldExtensions, newExtension ):
for name in os.listdir(path):
for oldExtension in oldExtensions:
if name.endswith(oldExtension):
name = os.path.join(path, name)
newName = name.replace(oldExtension, newExtension)
os.rename(name, newName)
break;
if __name__ == "__main__":
changeFileName( 'data', ['.py', '.rtf' , '.text', '.TEXT'], '.txt')
Use an array to store all the old extensions and iterate through them.
来源:https://stackoverflow.com/questions/34960343/how-to-change-multiple-filenames-in-a-directory-using-python