问题
Here is the sample data :
IdProduit Localisation Qte_EnMain
4266864286880063006 E2-R40-B-T 13.00000
4266864286880063006 E2-R45-B-T 81.00000
4266864286880063007 E2-R45-C-T 17.00000
4266864286880063008 E2-R37-B-T 8.00000
And this is what i would like to have
IdProduit AllLocalisation
4266864286880063006 E2-R40-B-T (13), E2-R45-B-T (81)
4266864286880063007 E2-R45-C-T (17)
4266864286880063008 E2-R37-B-T (8)
I watched all the examples of GROUP_CONCAT on the forum and I tried several tests.
I don't really understand STUFF().
Here is what i would like to do :
SELECT
a.IdProduit,
GROUP_CONCAT(
CONCAT(b.Localisation, ' (', CAST(ROUND(a.Qte_EnMain, 0) AS NUMERIC(36, 0)), ')')
) AS AllLocation
FROM
ogasys.INV_InventENTLoc a
LEFT JOIN ogasys.INV_LocName b ON a.IdLoc = b.IdLoc
GROUP BY a.IdProduit, b.Localisation, a.Qte_EnMain
Now because GROUP_CONCAT is nto working with MSSQL this is the query i have created with all example on this forum.
SELECT
DISTINCT
a1.IdProduit,
STUFF((SELECT DISTINCT '' + b2.Localisation
FROM
ogasys.INV_InventENTLoc a2
LEFT JOIN ogasys.INV_LocName b2 ON a2.IdLoc = b2.IdLoc
WHERE a2.IdLoc = a1.IdLoc
FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 0, '') data
FROM
ogasys.INV_InventENTLoc a1
LEFT JOIN ogasys.INV_LocName b1 ON a1.IdLoc = b1.IdLoc
ORDER BY a1.IdProduit
The query only return one localisation by row i don't understand how to make this query working.
EDIT:
Here is the solution for my situation :
SELECT
a.IdProduit,
STUFF(
(SELECT ', ' + b2.Localisation + ' (' + CAST(CAST(ROUND(a2.Qte_EnMain, 0) AS NUMERIC(36, 0)) AS VARCHAR(32)) + ')'
FROM ogasys.INV_InventENTLoc a2
LEFT JOIN ogasys.INV_LocName b2 ON a2.IdLoc = b2.IdLoc
WHERE a.IdProduit = a2.IdProduit
FOR XML PATH (''))
, 1, 1, '') AS AllLocalisation
FROM
ogasys.INV_InventENTLoc a
LEFT JOIN ogasys.INV_LocName b ON a.IdLoc = b.IdLoc
GROUP BY a.IdProduit
回答1:
using STUFF
declare @table table (IdProduit varchar(100), Localisation varchar(50), Qte_EnMain float)
insert into @table
values
('4266864286880063006','E2-R40-B-T', 13.00000),
('4266864286880063006','E2-R45-B-T', 81.00000),
('4266864286880063007','E2-R45-C-T', 17.00000),
('4266864286880063008','E2-R37-B-T', 8.00000)
select IdProduit,
STUFF (
(SELECT
',' + localisation + concat(' (',cast(qte_enMain as varchar(4)),') ')
FROM @table t2
where t2.IdProduit = t1.IdProduit
FOR XML PATH('')), 1, 1, ''
)
from @table t1
group by
IdProduit
来源:https://stackoverflow.com/questions/49784024/mssql-group-concat