问题
What works
Suppose I have a spring bean definition of an ArrayList:
<bean id="availableLanguages" class="java.util.ArrayList">
<constructor-arg>
<bean class="java.util.Arrays" factory-method="asList">
<constructor-arg>
<list>
<value>de</value>
<value>en</value>
</list>
</constructor-arg>
</bean>
</constructor-arg>
</bean>
Now I can inject this into all kinds of beans, e.g. like this:
@Controller
class Controller {
@Autowired
public Controller(ArrayList<String> availableLanguages) {
// ...
}
}
This works great.
How it breaks
However if I change my controller a tiny bit and use the type List
instead of ArrayList
like this:
@Controller
class Controller {
@Autowired
public Controller(List<String> availableLanguages) {
// ...
}
}
Then instead I get a list of all beans of type String
rather then the bean I defined. However I actually want to wrap my List into an unmodifiable List, but this will only be possible if I downgrade my dependency to a list.
So far discovered workaround
The following XML file:
<bean id="availableLanguages" class="java.util.Collections" factory-method="unmodifiableList">
<constructor-arg>
<bean class="java.util.Arrays" factory-method="asList">
<constructor-arg>
<list>
<value>de</value>
<value>en</value>
</list>
</constructor-arg>
</bean>
</constructor-arg>
</bean>
works together with this controller:
@Controller
class Controller {
@Autowired
public Controller(Object availableLanguages) {
List<String> theList = (List<String>)availableLanguages;
}
}
While this works the extra type cast is ugly.
Findings so far
I figured that there is a special handling for collections in Spring 4.2.5 (the currently most recent version) which seems to cause all the trouble. It creates special behaviour when a parameter is an interface that extends Collection
. Thus I can workaround by using Object
or a concrete implementation as parameter type.
Question
Is there any way to directly inject a list into a bean? How?
回答1:
Using @Qualifier will inject the bean with the given qualifier. You can name the list which you want to be a bean and that will work fine.
来源:https://stackoverflow.com/questions/36106804/how-can-i-inject-an-instance-of-list-in-spring