Polymorphic function as return value and value restriction in SML

问题

Basically, I want to have a function to return a polymorphic function, some thing like this:

fun foo () = fn x => x

So the foo function takes in a value of type unit and returns a polymorphic identity function and the compiler is happy with that, it gives me:

val foo = fn : unit -> 'a -> 'a

but once I actually call the foo function, the return value is not what I expected

val it = fn : ?.X1 -> ?.X2

Can't generalize because of value restriction it says, any help? thanks in advance

回答1:

For technical reasons, you are not allowed to generalize (i.e., make polymorphic) the results of a function call. The result of a call must have a monomorphic type. If this weren't the case, you could subvert the type system by the following dirty trick:

1. Call ref [] and get back a list of type forall 'a . 'a list ref
2. Insert a string.
3. Remove a function

and there you are: you are now executing the contents of an arbitrary string as code. Not Good.

By insisting that the value returned by ref [] be monomorphic, you ensure that it can be used as a list of strings or a list of functions but not both. So this is part of the price we pay for type safety.

来源：https://stackoverflow.com/questions/2150310/polymorphic-function-as-return-value-and-value-restriction-in-sml