问题
I want to switch from CreatMutex to boost::interprocess::named_mutex to limit my application to a single instance. Both methods works when the application runs and ends just fine. However, the lock is not released when the application crashes and using boost::interprocess::named_mutex. I could resolve that issue by using two name_mutex but I don't really understand the issue.
Why is the lock for boost::interprocess::named_mutex not released when the application crashes but it is release with CreatMutex? What's the difference?
boost::interprocess::named_mutex mutex(boost::interprocess::open_or_create, "my_mutex");
boost::interprocess::scoped_lock<boost::interprocess::named_mutex> lock(mutex, boost::interprocess::try_to_lock);
if(!lock) {
return 1; //exit
}
//application may crash here.
boost::interprocess::named_mutex::remove("my_mutex");
return 1; //exit
回答1:
Caveat: I've not spent much time with boost::interprocess, so this information is just from a quick inspection of the source. That said, I've used the Windows synchronisation API's a lot, so here goes...
The main difference between the two methods of interprocess synchronisation is how the object exists within the system.
With boost::interprocess::named_mutex, as well as a system-specific mutex, it looks like a synchronisation object is created as a file on the system. The location of the file is based on Registry entries (see note 1) (at least in Boost 1.54.0)... it's most likely located under the Common Application Data folder (see note 2). When the aplication crashes, this file is, in your case, not removed. I'm not sure if this is by design... however in the case of an application crash, it's perhaps best not to mess with the file system, just in case.
Conversely, when you use CreateMutex, an object is created at the kernel mode, which for named mutexes can be accessed by several applications. You get a handle to the Mutex by specifying the name when you create it, and you lose the handle when you call CloseHandle on it. The mutex object is destroyed when there are no more handles referencing it.
The important part of this is in the documentation:
The system closes the handle automatically when the process terminates. The mutex object is destroyed when its last handle has been closed.
This basically means that Windows will clean up after your application.
Note that if you don't perform a ReleaseMutex, and your application owns the mutex when it dies, then it's possible/likely that a waiting thread or process would see that the mutex had been abandoned (WaitForSingleObject returns WAIT_ABANDONED), and would gain ownership.
I apologise for not providing a solution, but I hope it answers your question about why the two systems act differently.
Just as an aside, using registry entries to get this information is horrible - it would be safer, and more future-proof, to use
SHGetKnownFolderPath. But I digress.Depending on your OS version, this could be
%ALLUSERSPROFILE%\Application Data\boost.interprocessorProgramData\boost.interprocess, or somewhere else entirely.
回答2:
What you want is not trivial and the interprocess_mutex definitively the wrong way to do.
What you may could do is remove the mutex on termination, by providing a remover destructor and/or in a catch(...). But this is not guaranteed to work, since it won't be done if you terminate the process directly (from the OS). Also it could accidently remove the mutex while your application starts twice.
One approach is to safe the process-id (for example in a shared memory) on the first time your program starts and remove it when it stops. Everytime you start the application read and check if the id still in process, if not, start the program.
来源：https://stackoverflow.com/questions/20379817/boostinterprocessnamed-mutex-vs-createmutex