x86 multi-byte NOP and instruction prefix

问题

As a small recall, the x86 architecture defines 0x0F 0x1F [mod R/M] as a multi-byte NOP.

Now I'm looking at the specific case of an 8-byte NOP: I have got

0x0F 0x1F 0x84 0x__ 0x__ 0x__ 0x__ 0x__

where the last 5 bytes have got arbitrary values.

The third byte, [mod R/M], split up gives:

mod = 10b: argument is reg1 + a DWORD-sized displacement
reg2 = 000b: (we don't care)
reg1 = 100b: indicates that the argument is instead the SIB byte + a DWORD-sized displacement.

Now, as a concrete example, if I take

0x0F 0x1F 0x84 0x12 0x34 0x56 0x78 0x9A

I've got

SIB = 0x12
displacement = 0x9A785634: a DWORD

Now I add the 0x66 instruction prefix to indicate that the displacement should be a WORD instead of a DWORD:

0x66 0x0F 0x1F 0x84 0x12 0x34 0x56 0x78 0x9A

I expect 0x78 0x9A to be 'cut off' and be treated as a new instruction. However, when compiling this and running objdump on the resulting executable, it still uses all 4 bytes (a DWORD) as displacement.

Am I misunderstanding the meaning of 'displacement' in this context? Or does the 0x66 prefix not have any effect on multi-byte NOP instructions?

回答1:

The 66H prefix overrides the size of the operand to 16 bit.
It does not override the size of the address, if you want that you use 67H

Here's a list of all operands.

        F0h = LOCK  -- locks memory reads/writes
        String prefixes
        F3h = REP, REPE  
        F2h = REPNE      
        Segment overrides
        2Eh = CS
        36h = SS
        3Eh = DS
        26h = ES
        64h = FS
        65h = GS
        Operand override 
        66h. Changes size of data expected to 16-bit
        Address override 
        67h. Changes size of address expected to 16-bit

However it is best not to create your own nop instructions, but stick to the recommended (multi-byte) nops.

According to AMD the recommended multibytes nops are as follows:

Table 4-9. Recommended Multi-Byte Sequence of NOP Instruction

bytes  sequence                encoding

 1      90H                            NOP
 2      66 90H                         66 NOP
 3      0F 1F 00H                      NOP DWORD ptr [EAX]
 4      0F 1F 40 00H                   NOP DWORD ptr [EAX + 00H]
 5      0F 1F 44 00 00H                NOP DWORD ptr [EAX + EAX*1 + 00H]
 6      66 0F 1F 44 00 00H             NOP DWORD ptr [AX + AX*1 + 00H]
 7      0F 1F 80 00 00 00 00H          NOP DWORD ptr [EAX + 00000000H]
 8      0F 1F 84 00 00 00 00 00H       NOP DWORD ptr [AX + AX*1 + 00000000H]
 9      66 0F 1F 84 00 00 00 00 00H    NOP DWORD ptr [AX + AX*1 + 00000000H]

Intel does not mind up to 3 redundant prefixes, so nop's up to 11 bytes can be constructed like so.

 10     66 66 0F 1F 84 00 00 00 00 00H     NOP DWORD ptr [AX + AX*1 + 00000000H] 
 11     66 66 66 0F 1F 84 00 00 00 00 00H  NOP DWORD ptr [AX + AX*1 + 00000000H]

Of course you can also eliminate nops by prefixing normal instructions with redundant prefixes.

e.g.

rep mov reg,reg //one extra byte

or forcing the cpu to use longer versions of the same instruction.

test r8d,r8d is one byte longer than: test edx,edx

The instructions with immediate operands have short and long versions.

and edx,7 //short
and edx,0000007  //long

Most assembler will helpfully shorten all instructions for you, so you'll have to code the longer instructions yourself using db

Interspersing these in strategic locations can help you align jump targets without having to incur delays due to the decoding or execution of a nop.

Remember on most CPU's executing nop's still uses up resources.

来源：https://stackoverflow.com/questions/27714524/x86-multi-byte-nop-and-instruction-prefix

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x86

prefix

nop