maven create zip with jar and some more files

问题

I do not understand maven. Better use ant, but... I've managed to create jar (with, or without dependencies), I've managed to copy bat runner script close to jar but now i want to create zip with this jar and this bat. So i use assembly plugin and get BUUUM!!!! CADAAAM! In my configuration it happens so, that it executes parallel to jar packaging. I wrote assembly file:

    <assembly
xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.0 http://maven.apache.org/xsd/assembly-1.1.0.xsd">
    <id>jg</id>
    <formats>
        <format>jar</format>
    </formats>
    <includeBaseDirectory>false</includeBaseDirectory>
    <fileSets>
        <fileSet>
            <directory>${project.build.directory}/classes</directory>
            <outputDirectory>/123</outputDirectory>
            <excludes>
                <exclude>assembly/**</exclude>
                <exclude>runners/**</exclude>
            </excludes>
        </fileSet>
    </fileSets>
    <dependencySets>
        <dependencySet>
            <outputDirectory>/</outputDirectory>
            <useProjectArtifact>true</useProjectArtifact>
            <unpack>true</unpack>
            <scope>runtime</scope>
        </dependencySet>
    </dependencySets>
</assembly>

Then, I bound maven-assembly-plugin:

<plugin>
        <artifactId>maven-assembly-plugin</artifactId>
        <version>2.2.1</version>
        <executions>
            <execution>
                <phase>package</phase>
                <goals>
                    <goal>single</goal>
                </goals>
                <inherited>false</inherited>
                <configuration>
                    <archive>
                        <manifest>
                            <mainClass>by.dev.madhead.lzwj.Main</mainClass>
                            <addClasspath>true</addClasspath>
                        </manifest>
                    </archive>
                    <descriptors>
                            <descriptor>src/main/resources/assembly/assembly.xml</descriptor>
                            <!-- <descriptorRef>jar-with-dependencies</descriptorRef> -->
                    </descriptors>
                </configuration>
            </execution>
        </executions>
    </plugin>

Now I get this in ./target:

runner.bat
jar_without_dependencies.jar (it is from maven-jar-plugin, right?)
jar_without_dependencies.jar

And the third angers me. It contains:

And the 123 directory contains:

As you see, I get jar with unpacked dependencies, EXCLUDED DIRS!!!!, and with dir 123, which is actually what I want (Oh! assembly plugin did that!!!).

I want to get jar with dependencies and correct manifest with classpath. As an option i want jar with unpacked dependencies (I know about <unpack>false</unpack> in assembly, but cannot get it work). I want to change /123 to / and get NORMAL JAR WITHOUT EXCLUDED FILES!!! I want two separate tasks to build jar and zip (is it done with profiles in maven??) As in ant, i would wrote something like this:

    <target name="jar_with_deps" depends-on="compile">
        <jar>
            here i copy classes (excluding some dirs with runner script), and build manifest
        </jar>
        <copy>
            copy bat file from src/main/resources/runner/runner.bat
        </copy>
    </target>
    <target name="zip" depends-on="jar_with_deps">
        <zip>
            Get jar from previous target, get runner.bat. Put them in zip
        </zip>
    </target>

Excuse me, if I am too expressive, but I am really angry with this implicit behavior. I am really stuck with this.

回答1:

You have to options to achieve your goal:

option: Create two assembly descriptors, one for jar w/ deps and one for zip. Zip takes the the newly created jar.
option: Create two more modules in your project: first modules shades all deps into one jar (or attach a shaded jar along with your main jar, save another module), have the second module depend on it and suck in that jar in your assembly. Your done.

Depending on the size and structure of your project, I would go for the safe way: option 2. This one is guaranteed to have the correct build and dep order. Option 1 violates the maven way somewhat.

回答2:

Just in case it helps anyone else, I found that this was pretty easy to do, at least for my basic needs. I was already using the Maven Shade plugin to build a jar with all dependencies included:

<plugin>
  <groupId>org.apache.maven.plugins</groupId>
  <artifactId>maven-shade-plugin</artifactId>
  <version>2.4.1</version>
  <configuration></configuration>
  <executions>
    <execution>
      <phase>package</phase>
      <goals>
        <goal>shade</goal>
      </goals>
    </execution>
  </executions>
</plugin>

So when I ran mvn package, it would produce target/MyApp-version.jar, whereas I wanted a MyApp-version.zip containing MyApp-version.jar along with some other files (a README, etc.). So, I add the Assembly plugin:

<plugin>
  <artifactId>maven-assembly-plugin</artifactId>
  <version>2.5.5</version>
  <configuration>
    <appendAssemblyId>false</appendAssemblyId>
    <descriptors>
      <descriptor>assembly.xml</descriptor>
    </descriptors>
  </configuration>
  <executions>
    <execution>
      <phase>package</phase>
      <goals>
        <goal>single</goal>
      </goals>
    </execution>
  </executions>
</plugin>

The above block refers to assembly.xml, which configures the way the plugin works:

<?xml version="1.0" encoding="utf-8"?>
<assembly xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.3"
      xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
      xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.3 http://maven.apache.org/xsd/assembly-1.1.3.xsd">
    <id>release</id>
    <formats>
        <format>zip</format>
    </formats>
    <fileSets>
        <fileSet>
            <directory>target</directory>
            <includes>
                <include>MyApp-${app.version}.jar</include>
            </includes>
            <outputDirectory>/</outputDirectory>
        </fileSet>
    </fileSets>
    <files>
        <file>
            <source>CHANGES.md</source>
            <fileMode>0644</fileMode>
        </file>
        <file>
            <source>LICENSE</source>
            <fileMode>0644</fileMode>
        </file>
        <file>
            <source>README</source>
            <fileMode>0644</fileMode>
        </file>
    </files>
</assembly>

(${app.version} is defined in the pom.xml <properties> element.)

That's it, now mvn package produces both the jar and the zip.

回答3:

I've made two profiles in pom.xml:

<profiles>
    <profile>
        <id>jar-with-dependencies</id>
        <activation>
            <activeByDefault>false</activeByDefault>
        </activation>
        <build>
            <plugins>
                <plugin>
                    <artifactId>maven-assembly-plugin</artifactId>
                    <version>2.2.1</version>
                    <configuration>
                        <archive>
                            <manifest>
                                <mainClass>by.dev.madhead.lzwj.Main</mainClass>
                            </manifest>
                        </archive>
                        <descriptorRefs>
                            <descriptorRef>jar-with-dependencies</descriptorRef>
                        </descriptorRefs>
                    </configuration>
                    <executions>
                        <execution>
                            <phase>package</phase>
                            <goals>
                                <goal>single</goal>
                            </goals>
                        </execution>
                    </executions>
                </plugin>
            </plugins>
        </build>
    </profile>
    <profile>
        <id>distro</id>
        <activation>
            <activeByDefault>false</activeByDefault>
        </activation>
        <build>
            <plugins>
                <plugin>
                    <artifactId>maven-assembly-plugin</artifactId>
                    <version>2.2.1</version>
                    <configuration>
                        <descriptors>
                            <descriptor>src/main/assembly/distro.xml</descriptor>
                        </descriptors>
                    </configuration>
                    <executions>
                        <execution>
                            <phase>package</phase>
                            <goals>
                                <goal>single</goal>
                            </goals>
                        </execution>
                    </executions>
                </plugin>
            </plugins>
        </build>
    </profile>
</profiles>

Now i am able to create simple jar (mvn clean package), jar with dependencies (mvn clean package -Pjar-with-dependencies). I also can call mvn package -Pdistro to create zip. But i need to call maven with -Pjar-with-dependencies before it manually. Except this, everything is ok.

来源：https://stackoverflow.com/questions/8281941/maven-create-zip-with-jar-and-some-more-files

标签

maven

maven-3

maven-assembly-plugin

maven-jar-plugin