LeetCode：Employees Earning More Than Their Manager

1、题目名称

Employees Earning More Than Their Managers（比领导工资还高的员工）

2、题目地址

https://leetcode.com/problems/employees-earning-more-than-their-managers/

3、题目内容

Employee表的结构包含四列：Id、Name、Salary、ManagerId，找出其中工资高于直接上级的员工的Name。

例如，下表中Joe的工资大于他的直接上级Sam：

+----+-------+--------+-----------+
| Id | Name  | Salary | ManagerId |
+----+-------+--------+-----------+
| 1  | Joe   | 70000  | 3         |
| 2  | Henry | 80000  | 4         |
| 3  | Sam   | 60000  | NULL      |
| 4  | Max   | 90000  | NULL      |
+----+-------+--------+-----------+

4、初始化数据库脚本

在MySQL数据库中建立一个名为LEETCODE的数据库，用MySQL命令行中的source命令执行下面脚本：

-- 执行脚本前必须建立名为LEETCODE的DATABASE
USE LEETCODE;

DROP TABLE IF EXISTS Employee;
CREATE TABLE Employee (
    Id INT NOT NULL PRIMARY KEY,
    Name VARCHAR(50),
    Salary INT,
    ManagerId INT
);

INSERT INTO Employee (Id, Name, Salary, ManagerId) VALUES (1, 'Joe', 70000, 3);
INSERT INTO Employee (Id, Name, Salary, ManagerId) VALUES (2, 'Henry', 80000, 4);
INSERT INTO Employee (Id, Name, Salary, ManagerId) VALUES (3, 'Sam', 60000, NULL);
INSERT INTO Employee (Id, Name, Salary, ManagerId) VALUES (4, 'Max', 90000, NULL);

5、解题SQL

解题SQL如下：

SELECT Name
FROM Employee AS A
WHERE Salary > (
  SELECT Salary
  FROM Employee AS B
  WHERE Id = A.ManagerId
);

END

来源：oschina

链接：https://my.oschina.net/u/1425762/blog/493127

标签

leetcode

#181

sql

工资比较